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3 years ago

-4(-6 + 4b) simplified

Mathematics

1 answer:

WITCHER [35]3 years ago

3 0

It is 24+6b im writing more because it says to put more cause my answer is to "short"

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What is 45/76 simplified

adelina 88 [10]

<span> 45/76 = 0.59211 76
You just had to divide the numerator by the denominator
Hope I helped:)
Mark me as brainliest if I helped

</span>

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3 years ago

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What is the expression in factored form?

san4es73 [151]

Answer: (4x + 3) (x + 2)

Step-by-step explanation:

We can rewrite 4x² + 11x + 6 as 4x² + 8x + 3x + 6

Since 4x² + 11x + 6 = 4x² + 8x + 3x + 6

= (4x + 3) (x + 2)

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3 years ago

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The following equation is often referred to as Euler's Formula; e^pii+1=0 Use what you know about complex numbers to show that t

Sav [38]

Answer:

$\large \boxed{e^{i\pi}+1=0}$

Step-by-step explanation:

Hello, please consider the following.

For any x real number,

$e^{ix}=cos(x)+i\cdot sin(x)\text{, right? So}\\\\e^{i\pi}=cos(\pi)+i\cdot sin(\pi)\\\\e^{i\pi}=-1+i\cdot 0=-1\\\\\text{ We add 1 to both sides of the equation.}\\\\\large \boxed{e^{i\pi}+1=0}\\$

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

6 0

3 years ago

Don’t understand this question will give brainless thing

____ [38]

The answer is 6.33 units.

4 0

2 years ago

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In how many arrangements can 3 boys and 4 girls stand in a row such that no two boys are together?

Sophie [7]

Answer: 1440

Step-by-step explanation:

To arrange 3 boys and 4 girls such that no two boys are together.

Since boys should be arranged between the girls.

So first arrange the girls.

Assume that the girls are placed, then there will be 5 spaces left for 3 boys.

The number of combinations to fill these places = $^5C_3=\dfrac{5!}{3!2!}=\dfrac{5\times4}{2}=10$

Also, 3 boys can arrange themselves in 3! =3 x 2 x 1 = 6 ways

4 girls can arrange themselves in 4! = 4x 3 x 2 x 1 = 24 ways

Then, the total number of arrangements = 10 x 6 x 24 = 1440

Hence, the required number of arrangements = 1440

5 0

3 years ago