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Serggg [28]
3 years ago
12

Could a vector ever be shorter than one of its components? Equal in length to one of its components? Explain.

Physics
2 answers:
yaroslaw [1]3 years ago
7 0
It can never be shorter than a component - magnitude of a vector is the square root of the sum of the components squared, and a square function never produces a negative number. However, it can be the same size as it's component, if that component is the only one.
Vitek1552 [10]3 years ago
5 0

Answer:Consider the graph and equation, y = 3x, that represent Alonso’s walking speed. What relationship is represented by this equation and graph? What would the points (3, 9) and (5, 15) represent?

Explanation:

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A 400g mass object at rest is acted on by a 200 N net force for 12 seconds. What is it’s final velocity?
Kisachek [45]

Explanation:

do we can say that the first step is finding the acceleration of the object. We do so by saying F = ma

so a = F/m

a = 500 m/s^2

we now have the time, acceleration and initial velocity.

so we can find the final velocity by using one of newtons equations which is: vf = vi + at

so:

vf = 0 + 500 × 12

vf = 6000

note that our initial velocity was zero since the object was initially at rest.

if you still have any doubt dont hesitate to ask for further help.

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2 years ago
How did Newton use creativity and logic in his approach to investigating light?
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He used the quantum mechanic theory to approach light by describing relativity and perspective.
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Why should people pay attention to scientists when making decisions? A)scientist are the smartest people B) Scientist make up fa
MrRa [10]

Answer:

C) scientist use experiments to test their ideas

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4 years ago
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Astronomers study radio waves to learn about
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4 years ago
The coefficient of friction between a rider and the merry go round is 0.45 and the person is measured to be traveling at 20.0 RP
svlad2 [7]

The person must stand at a radius of 0.99 m

Explanation:

In order for the person to stand on the merry go round, the force of friction acting on the person must provide the centripetal force necessary to keep the person in uniform circular motion.

Therefore, we can write:

\mu mg = m\omega^2 r

where:

- the term on the left is the force of friction, and the term on the right is the centripetal force

\mu = 0.45 is the coefficient of friction

m is the mass of the person

g=9.8 m/s^2 is the acceleration of gravity

\omega = 20 \frac{rev}{min} \cdot \frac{2\pi rad/rev}{60 s/min}=2.09 rad/s is the angular velocity

r is the radius of the circular path

Solving the equation for r, we find the radius at which the person must be standing:

r=\frac{\omega^2}{\mu g}=\frac{(2.09)^2}{(0.45)(9.8)}=0.99 m

Learn more about circular motion:

brainly.com/question/2562955

brainly.com/question/6372960

#LearnwithBrainly

8 0
3 years ago
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