<u>Answer:</u> The additional information that is helpful in calculating the mole percent of XCl(s) and ZCl(s) is the molar masses of Z and X
<u>Explanation:</u>
To calculate the mole percent of a substance, we use the equation:
Mass percent means that the mass of a substance is present in 100 grams of mixture
To calculate the number of moles, we use the equation:
We require the molar masses of Z and X to calculate the mole percent of Z and X respectively
Hence, the additional information that is helpful in calculating the mole percent of XCl(s) and ZCl(s) is the molar masses of Z and X
Tin(II) fluoride or stannous fluoride
Answer:
3.864 g of C₃H₆
Explanation:
The balanced equation for the reaction is given below:
2C₃H₆ + 9O₂ —> 6CO₂ + 6H₂O
From the balanced equation above,
2 moles of C₃H₆ reacted to produce 6 moles of CO₂
Next, we shall determine the number of mole of C₃H₆ that reacted to produce 0.276 mole of CO₂. This can be obtained as follow:
From the balanced equation above,
2 moles of C₃H₆ reacted to produce 6 moles of CO₂.
Therefore, Xmol of C₃H₆ will react to produce 0.276 moles of CO₂ i.e
Xmol of C₃H₆ = (2 × 0.276)/6
Xmol of C₃H₆ = 0.092 mole
Finally, we shall determine the mass of 0.092 mole of C₃H₆. This can be obtained as follow:
Mole of C₃H₆ = 0.092 mole
Molar mass of C₃H₆ = (12×3) + (6×1)
= 36 + 6
= 42 g/mol
Mass of C₃H₆ =?
Mass = mole × molar mass
Mass of C₃H₆ = 0.092 × 42
Mass of C₃H₆ = 3.864 g
Therefore, 3.864 g of C₃H₆ is needed for the reaction.
The answer is <span>D.territorial behavior</span>
The answer is c O2:H2O
502:6H2O
SO THAT IS 5:6
