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suter [353]
3 years ago
11

What pressure is exerted by 932.3 g of CH4 in a 0.560 L steel container at 136.2 K?

Chemistry
1 answer:
Roman55 [17]3 years ago
5 0
Molar mass CH4 = 16.0 g/mol

* number of moles:

932.3 / 16 => 58.26875 moles

T = 136.2 K

V = 0.560 L

P = ?

R = 0.082

Use the clapeyron equation:

P x V = n x R x T

P x 0.560 =  58.26875 x 0.082 x 136.2

P x 0.560 = 650.76

P = 650.76 / 0.560

P = 1162.07 atm
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