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Rainbow [258]
3 years ago
15

Eight times the sum of a number and 3 is 9

Mathematics
1 answer:
Ivanshal [37]3 years ago
6 0

Answer:

<u>8(n + 3) = 9</u>

Step-by-step explanation:

  8

  ∨        ×       →  (                   n         +  3) = 9    

Eight times the sum of a number and 3 is 9

--------------------------------------------------------------------------------

8(n + 3) = 9

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Alisa has a bunch of coins. She has pennies. She has nickels. She has dimes. She has quarters. They lie in one big pile. Alisa w
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Answer:

E. Not enough info.

Step-by-step explanation:

There could be 2 quarters 500 nickels and 7 pennies or 800 pennies 50 quarters and 2 nickels.

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3 years ago
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find the value of the polygon. the polygon has 6 interior angles 2 of them are y and 4 of them are (2Y-20)
Anna35 [415]
First we need to determine what the 6 angles must add to. Turns out we use this formula

S = 180(n-2)

where S is the sum of the angles (result of adding them all up) and n is the number of sides. In this case, n = 6. So let's plug that in to get

S = 180(n-2)
S = 180(6-2)
S = 180(4)
S = 720

The six angles, whatever they are individually, add to 720 degrees. The six angles are y, y, 2y-20, 2y-20,  2y-20,  2y-20, <span> 

They add up and must be equal to 720, so let's set up the equation to get...

(y)+(y)+(</span>2y-20)+(2y-20)+(2y-20)+(<span>2y-20) = 720

Let's solve for y

</span>y+y+2y-20+2y-20+2y-20+2y-20 = 720

10y-80 = 720

10y-80+80 = 720+80

<span>10y = 800
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10y/10 = 800/10

y = 80

Now that we know the value of y, we can figure out the six angles

angle1 = y = 80 degrees
<span>angle2 = y = 80 degrees
</span><span>angle3 = 2y-20 = 2*80-20 = 140 degrees
</span>angle4 = 2y-20 = 2*80-20 =<span> 140 degrees
</span><span>angle5 = 2y-20 = 2*80-20 = 140 degrees
</span>angle6 = 2y-20 = 2*80-20 =<span> 140 degrees
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3 0
4 years ago
Need Help ASAP!!!
Hitman42 [59]

Answer:

The answer to your question is:

x = 1

y = 1

z = 0

Step-by-step explanation:

                                -2x + 2y + 3z = 0             (1)

                                -2x - y + z = -3                  (2)

                                 2x + 3y + 3z = 5              (3)

Solve (1) and (2)  

Multiply 2 by 2

                                 -2x + 2y + 3z = 0

                                 -4x -2y   + 2z = -6

                                -6x          + 5 z = -6        (4)

Solve (2) and (3)

Multiply 2 by 3

                               -6x - 3y + 3z = -9

                                2x + 3y + 3z = 5

                               -4x         + 6z = -4           (5)

Solve (4) and (5)

Multiply (4) by 2 and (5) by -3

                           -12x    + 10 z = -12

                            12x    -  18z   = 12

                                         -6z = 0

                                          z = 0

Then

            -4x + 6(0) = -4

           -4x = -4

            x = -4/-4

            x = 1

Finally

                 -2(1) - y + (0) = -3      

                -2 - y = -3

                 -y = -3 + 2

                 y = 1  

   

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