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Elden [556K]
3 years ago
13

1 + x to the 0th power.

Mathematics
1 answer:
lutik1710 [3]3 years ago
8 0
Is 0 because it's to the power of zero
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Delicious77 [7]
There are 42 kids in one classroom. They are all divided into 3 groups. How many kids will be in each group?
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3 years ago
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The following function describes the number of employees working at a company, In thousands, where trepresents the number of yea
NISA [10]

Consider the missing part of the question is "Select the correct statement.

A. The number of employees is increasing by 50% every year.

B. The number of employees is decreasing by 10% every year.

C. The number of employees is decreasing by 90% every year.

D. The number of employees is increasing by 90% every year."

Given:

The function is:

f(t)=1.5(0.90)^t

Where, f(t) is the number of employees working at a company, in thousands and t is the number of years since the company revised the benefits package.

To find:

The correct statement from the given options.

Solution:

The general exponential decay model is:

f(t)=a(1-r)^t         ...(i)

Where, a is the initial value, r is the rate of decay and t is the number of years.

We have,

f(t)=1.5(0.90)^t

It can be written as

f(t)=1.5(1-0.10)^t        ...(ii)

From (i) and (ii), we get

a=1.5,r=0.10

The initial value is 1.5 and the rate of decay is 0.10 or 10%. It means the number of employees is decreasing by 10% every year.

Therefore, the correct option is B.

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3 years ago
What is the proper mathematical definition of "square root?"
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The square root<span> of a number is a value that, when multiplied by itself, gives the number.</span><span> </span>
6 0
3 years ago
One hundred items are simultaneously put on a life test. Suppose the lifetimes
romanna [79]

Answer:

a) \mathrm{E}[\mathrm{T}]=\sum_{\mathrm{H}}^{5} \frac{200}{101-i}

b) \mathrm{Var}[\mathrm{T}]=\sum_{k=1}^{5} \frac{(200)^{2}}{(101-i)^{2}}

Step-by-step explanation:

Given:

The lifetimes of the individual items are independent exponential random variables.

Mean = 200 hours.

Assume, Ti be the time between ( i-1 )st and the ith failures. Then, the T_{i} are independent with \mathrm{T}_{\mathrm{i}} being exponential with rate \frac{(101-i)}{200} .

Therefore,

a) E[T]=\sum_{i=1}^{5} E\left[\tau_{i}\right]

=\sum_{i=1}^{5} \frac{200}{101-i}

\therefore \mathrm{E}[\mathrm{T}]=\sum_{\mathrm{H}}^{5} \frac{200}{101-i}

b)

The variance is given by, \mathrm{Var}[\mathrm{T}]=\sum_{i=1}^{5} \mathrm{Var}[T]

\therefore \mathrm{Var}[\mathrm{T}]=\sum_{k=1}^{5} \frac{(200)^{2}}{(101-i)^{2}}

7 0
3 years ago
Trigonometry
Alchen [17]

The area of the triangle PQR is 17.6 square units.

Explanation:

Given that the sides of the triangle are PQ = 12 and PR = 3 and m\angle P = 78^{\circ}

We need to determine the area of the triangle PQR

<u>Area of the triangle:</u>

The area of the triangle can be determined using the formula,

\text {Area}=\frac{1}{2} qr \sin P

Substituting the values, we get,

\text {Area}=\frac{1}{2}(12)(3) \sin 78

Simplifying, we have,

\text {Area}=\frac{1}{2}(36)(0.98)

Multiplying the terms, we have,

\text {Area}=\frac{35.28}{2}

Dividing, we get,

\text {Area}=17.64

Rounding off to the nearest tenth, we have,

Area=17.6

Thus, the area of the triangle PQR is 17.6 square units.

3 0
3 years ago
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