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GrogVix [38]
2 years ago
13

For this type of question, do you need a graph to figure out the solution or is there another non graphical way to know which is

the top and bottom function? I used desmos to graph the functions but how would you do this question without looking at desmos?

Mathematics
1 answer:
hoa [83]2 years ago
3 0

Step-by-step explanation:

First, find the intersections.

4x = x³

0 = x³ − 4x

0 = x (x² − 4)

0 = x (x + 2) (x − 2)

x = -2, 0, 2

So we will consider two intervals: -2 ≤ x ≤ 0, and 0 ≤ x ≤ 2.

Pick a point within each interval and evaluate both functions at that point.  Compare to see which function is greater.

At x = -1, y₁ = 4x = -4, and y₂ = x³ = -1.  So y₂ > y₁.

At x = 1, y₁ = 4x = 4, and y₂ = x³ = 1.  So y₁ > y₂.

So the integral would be:

∫₋₂⁰ (x³ − 4x) dx + ∫₀² (4x − x³) dx

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D, (1,2)

Step-by-step explanation:

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2 years ago
Find the difference quotient <img src="https://tex.z-dn.net/?f=%5Cfrac%7Bf%28x%20%2B%20h%29%20-%20f%28x%29%7D%7Bh%7D" id="TexFor
AlladinOne [14]

Answer:

-2x - h - 3

Step-by-step explanation:

Step 1: Define

Difference Quotient: \frac{f(x+h)-f(x)}{h}

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f(x + h) means that x = (x + h)

f(x) is just the normal function

Step 2: Find difference quotient

  1. <u>Substitute:</u> \frac{[-(x+h)^2-3(x+h)+1]-(-x^2-3x+1)}{h}
  2. <u>Expand and Distribute:</u> \frac{[-(x^2+2hx+h^2)-3x-3h+1]+x^2+3x-1}{h}
  3. <u>Distribute:</u> \frac{-x^2-2hx-h^2-3x-3h+1+x^2+3x-1}{h}
  4. <u>Combine like terms:</u> \frac{-2hx-h^2-3h}{h}
  5. <u>Factor out </u><em><u>h</u></em><u>:</u> \frac{h(-2x-h-3)}{h}
  6. <u>Simplify:</u> -2x - h - 3

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