The magnetic field lines outside a bar magnet

1 answer:

n200080 [17]3 years ago

8 0

The lines of magnetic field from a bar magnet form closed lines. By convention, the field direction is taken to be outward from the North pole and in to the South pole of the magnet.

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Which statement best describes electrons?

crimeas [40]

They are positive and remain inside the nucleus.

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2 years ago

How do landforms and rock layers support the plate tectonic theory

Debora [2.8K]

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Please give Brainliest!

3 0

3 years ago

a car travelling at 50km/h from rest covers a distance of 10km in 40minutes. Calculate the acceleration

Margarita [4]

Answer:

$9.67\cdot 10^{-3}m/s^2$

Explanation:

We can solve the problem by using the following suvat equation:

$v^2-u^2=2as$

where

v is the final velocity

u is the initial velocity

a is the acceleration

s is the displacement

For the car in this problem:

u = 0 (it starts from rest)

$v=50 km/h \cdot \frac{1000}{3600}=13.9 m/s$ is the final velocity

s = 10 km = 10 000 m is the displacement

Solving for a, we find:

$a=\frac{v^2-u^2}{2s}=\frac{13.9^2}{2(10000)}=9.67\cdot 10^{-3}m/s^2$

7 0

3 years ago

If you increase the charge on a parallel-plate capacitor from 3 mu or micro CC to 9 mu or micro CC and increase the plate separa

aliya0001 [1]

Explanation:

The energy stored in a capacitor is given by

$U = \dfrac{1}{2}QV = \dfrac{Q^2}{2C}$

In the case of a parallel plate capacitor, the capacitance C is given by

$C = \dfrac{\epsilon_0A}{d}$

so we can rewrite the expression for the energy as

$U = \dfrac{Q^2d}{2\epsilon_0 A}$

Increasing the charge from $3\:\mu\text{C}\:\text{to}\:9\:\mu\text{C}$ means that you're tripling the charge. The same thing is true when you increase the distance from 1.8 mm to 5.4 mm, i.e., you triple the separation distance. So the new energy U' is given by