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Ilya [14]
3 years ago
11

Name 2 forces acting on an object at rest Only need 1 got gravity

Physics
1 answer:
mote1985 [20]3 years ago
7 0

You mean like a box sitting on a table.

One force is the force of gravity, pulling downward on the box.

Now, you know that the forces acting on the box must be balanced, because
if they're not, then the box would be accelerating.  But it's just sitting there, so
there must be some other force, just exactly the right strength and direction to
exactly cancel the force of gravity on the box, so that the net force on it is zero.

The other force is the force of the table pushing upward on the box.  It's called
the "normal force".


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Lol i'm going to fail please help
Novosadov [1.4K]

Answer:

Explanation:

The frequency is 16.0 Hz. That means that 16 of these waves can pass a single point in 1 second. We are given frequency and wavelength. The equation that relates them is

f=\frac{v}{\lambda} where f is frequency, v is velocity, and λ is wavelength. Putting all this together:

16.0=\frac{v}{97.5} and solving for velocity,

v = 16.0(97.5) so

v = 1560 m/s. This wave can travel 1560 meters in a single second!!! Now that we know this velocity, we can use it in a proportion to find our unknown, which is how long, t, it will take to hear this sound 11000m away. (11 km is 11000m):

\frac{1560m}{1s}=\frac{11000}{t} and cross multiply to get

1560t = 11000 so

t = 7.1 seconds

6 0
3 years ago
What is the frequency of a transverse wave ?​
yuradex [85]

Answer:

The number of complete vibration or wave made in

one second is called frequency.

7 0
3 years ago
A coil of area 0.320 m2 is rotating at 100 rev/s with the axis of rotation perpendicular to a 0.430 T magnetic field. If the coi
weqwewe [10]

Answer:

The maximum  emf generated in the coil is 60527.49 V

Explanation:

Given;

area of coil, A = 0.320 m²

angular frequency, f = 100 rev/s

magnetic field, B = 0.43 T

number of turns, N = 700 turns

The maximum emf generated in the coil is calculated as,

E = NBAω

where;

ω is the angular speed = 2πf

E = NBA(2πf)

Substitute in the given values and solve for E

E = 700 x 0.43 x 0.32 x 2π x 100

E = 60527.49 V

Therefore, the maximum  emf generated in the coil is 60527.49 V

8 0
3 years ago
What is the speed of the wave above of the frequency is 7.0 hertz
alexandr1967 [171]

Answer:

Umm

Explanation:

3 0
3 years ago
A baseball is launched horizontally from a height of 1.8 m. The baseball travels 0.5 m before hitting the ground. How fast is th
zysi [14]

Answer:

0.83 m/s

Explanation:

FIrst of all, we have to find the time of flight, i.e. the time the baseball needs to reach the ground. This can be done by using the equation for the vertical motion:

h=ut+\frac{1}{2}gt^2

where

h is the initial height

u = 0 is the initial vertical velocity

g = 9.8 m/s^2 is the acceleration of gravity

t is the time

Substituting h = 1.8 m and solving for t,

t=\sqrt{\frac{2h}{g}}=\sqrt{\frac{2(1.8)}{9.8}}=0.61 s

We know that the horizontal distance travelled by the ball is

d = 0.5 m

Therefore, we can find the horizontal velocity (which is constant during the whole motion):

v= \frac{d}{t}=\frac{0.5}{0.60}=0.83 m/s

4 0
3 years ago
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