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Nat2105 [25]
3 years ago
15

Near the end of a marathon race, the first two runners are separated by a distance of 45.6 m. The front runner has a velocity of

3.1 m/s, and the second a velocity of 4.65 m/s. How many seconds earlier will the second runner reach the finish line if the front runner is 250 m from the finish line in seconds?
Physics
1 answer:
morpeh [17]3 years ago
3 0

Answer:17.08 s

Explanation:

Given

distance between First and second Runner is 45.6 m

speed of first runner(v_1)=3.1 m/s

speed of second runner(v_2)=4.65 m/s

Distance between first runner and finish line is 250 m

Second runner need to run a distance of 250+45.6=295.6 m

Time required by second runner t=\frac{295.6}{4.65}=63.56 s

time required by first runner to reach finish line=\frac{250}{3.1}=80.64 s

Thus second runner reach the finish line 80.64-63.56=17.08 s earlier

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alexandr402 [8]

False

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3 years ago
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How do vafiations in electronegativity result in the unequal sharign of electrons in polar molecuels?
nirvana33 [79]

Answer and Explanation:

Polar molecules are formed as a result of unequal sharing of electrons by the atoms in the molecule which creates polarization like that in water molecule.

If the electrons are shared equally by the atoms in the molecule then there won't be any polarization of the molecule and the molecule is non polar.

Electro-negativity is that property of an atom which lets it attract negative charges, i.e., electrons. The more the electro-negativity of an atom in the molecule the more are the chances of its polarization.

5 0
2 years ago
61. A physics student has a single-occupancy dorm room. The student has a small refrigerator that runs with a current of 3.00 A
Mademuasel [1]

Answer:

Part a)

percentage = 21.3%

Part b)

percentage = 2.13 \times 10^{-5}%

Explanation:

As we know that total power used in the room is given as

P = P_1 + P_2 + P_3 + P_4

here we have

P_1 = (110)(3) = 330 W

P_2 = 100 W

P_3 = 60 W

P_4 = 3 W

P = 330 + 100 + 60 + 3

P = 493 W

Part a)

Since power supply is at 110 Volt so the current obtained from this supply is given as

110\times i = 493

i = 4.48 A

now resistance of transmission line

R = \frac{\rho L}{A}

R = \frac{(2.8 \times 10^{-8})(10\times 10^3)}{\pi(4.126\times 10^{-3})^2}

R = 5.23 \ohm

now power loss in line is given as

P = i^2 R

P = (4.48)^2(5.23)

P = 105 W

Now percentage loss is given as

percentage = \frac{loss}{supply} \times 100

percentage = \frac{105}{493} \times 100

percentage = 21.3%

Part b)

now same power must have been supplied from the supply station at 110 kV, so we have

110 \times 10^3 (i ) = 493

i = 4.48\times 10^{-3} A

now power loss in line is given as

P = i^2 R

P = (4.48 \times 10^{-3})^2(5.23)

P = 1.05 \times 10^{-4} W

Now percentage loss is given as

percentage = \frac{loss}{supply} \times 100

percentage = \frac{1.05 \times 10^{-4}}{493} \times 100

percentage = 2.13 \times 10^{-5}%

6 0
3 years ago
A student pushes a 12.0 kg box with a horizontal force of 20 N. The friction force on the box is 9.0 N. Which of the following i
Hoochie [10]

The acceleration of the box is approximately 1 m/s^2

Explanation:

According to Newton's second law of motion, the net force acting on the box is equal to the product between its mass and its acceleration:

\sum F = ma

where

\sum F is the net force

m = 12.0 kg is the mass of the box

a is the acceleration

The net force can be written as

\sum F = F_a - F_f

where

F_a = 20 N is the applied forward force

F_f=9.0 N is the friction force

Combining the two equations,

F_a-F_f=ma

And solving for the acceleration,

a=\frac{F_a-F_f}{m}=\frac{20-9}{12}=0.9 m/s^2\sim 1 m/s^2

Learn more about Newton's second law:

brainly.com/question/3820012

#LearnwithBrainly

8 0
3 years ago
A bullet is fired into the air at an angle of 30° to the horizontal. At the same time and from the same height,
enyata [817]

Answer:

The bullet that is fired will spend longer  in the air, hitting the ground after the  dropped bullet.

Explanation:

Using the equation: x =  x 0  +   v t

If we neglect the effects of air resistance, the horizontal motion is a constant velocity.

The horizontal displacement = (velocity X cosθ)

So, the fired bullet has to travel horizontally before falling which takes a  longer time compared to a bullet dropped where it is, height = 1/2 gt^2

gravity, g = 9.8 m/s2.

3 0
2 years ago
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