Answer:
Q = 114895 J
Explanation:
To find the thermal energy gained by the ice you use the following formula:

m: mass of the ice = 0.250kg
T2: final temperature = 22°C
T1: initial temperature = -8.0°C
Hf: heat of fusion of water = 3.34*10^5 J/kg
c: specific heat of water = 4186 J/kg
By replacing the values of the parameters you have:

where you have considered that ice melts completely
Most common are destructive tests, such as stress, fatigue and micro sectioning tests. There are also methods that allow non-destructive testing (NDT), so the material can be still be used after testing. Common methods are ultrasonic, X-ray, HF Eddy Current, Radio Wave testing or thermography.
Answer:



Explanation:
Given:
- Length of block,

- Breadth of block,

- height of block,

- Thermal conductivity of the block,

- Temperature on the hotter side,

- temperature on the cooler side,

- time for which the heat flows,

<u>REFER THE ATTACHED IMAGE FOR THE REFERENCE</u>
<em>The rate of heat flow using </em><em>Fourier's law</em><em> of conduction is given as:</em>

<u>Now the amount heat flow perpendicular to the pink surface:</u>


<u>Now the amount heat flow perpendicular to the orange surface:</u>


<u>Now the amount heat flow perpendicular to the green surface:</u>

