Choose the following function that belongs to the squaring family. y = x 3 + x 2 y = x 2 - x y = x + 22 y =
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ΔABC has two congruent angles. Therefore, it is an isosceles triangle.
Therefore we have the equation (1) 3x - 5 = y + 12.
All angles of the ΔDBC are congruent. Therefore it is an equilateral triangle.
Therefore we have the equation (2) 3x - 5 = 5y - 4
From (1) and (2) we have the equation:
5y - 4 = y + 12 <em>add 4 to both sides</em>
5y = y + 16 <em>subtract y from both sides</em>
4y = 16 <em>divide both sides by 4</em>
y = 4
Substitute the value of y to (1):
3x - 5 = 4 + 12
3x - 5 = 16 <em>add 5 to both sides</em>
3x = 21 <em>divide both sides by 3</em>
x = 7
<h3>Answer: x = 7 and y = 4</h3>
This is what I got I tried to underline to show u what I was doing and and how I did it
