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2 years ago

364 - 127 I AM IN 2ND NOT MIDDLE SCHOOL

Mathematics

2 answers:

Vlad1618 [11]2 years ago

7 0

Answer:

237

Step-by-step explanation:

Stella [2.4K]2 years ago

5 0

The answer is 237, because 364-127=237

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mote1985 [20]

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Step-by-step explanation:

Recall the formula for the sine of the double angle:

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$cos^2(\theta)+sin^2(\theta)=1\\sin^2(\theta)=1-cos^2(\theta)\\sin(\theta)=\sqrt{1-cos^2(\theta)} \\sin(\theta)=\sqrt{1-(\frac{3}{18} )^2}\\sin(\theta)=\sqrt{1-\frac{9}{324} }\\sin(\theta)=\sqrt{\frac{324-9}{324} }\\sin(\theta)=\sqrt{\frac{315}{324} }\\\\sin(\theta)=\frac{3}{18}\sqrt{35 }$

With this information, we can now complete the value of the sine of the double angle requested:

$sin(2\theta)=2*sin(\theta)*cos(\theta)\\sin(2\theta)=2*\frac{3}{18} \,\sqrt{35} \,\frac{3}{18}\\sin(2\theta)=\frac{2*3*3}{18*18}\,\sqrt{35} \\sin(2\theta)=\frac{\sqrt{35} }{18}$

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3 years ago

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364 - 127 I AM IN 2ND NOT MIDDLE SCHOOL​

364 - 127 I AM IN 2ND NOT MIDDLE SCHOOL