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Sonja [21]
2 years ago
14

What is the volume of this prism?

Mathematics
2 answers:
HACTEHA [7]2 years ago
7 0

Answer:

Step-by-step explanation:The formula for the volume of a prism is V=Bh , where B is the base area and h is the height. The base of the prism is a rectangle. The length of the rectangle is 9 cm and the width is 7 cm. The area A of a rectangle with length l and width w is A=lw .

balu736 [363]2 years ago
6 0
B. 56.3 because 5x3x3.75 is 56.25 and then you round the 2 to 3 because a 5 follows it
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MissTica
Yes because they're the same
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Bowling alley A charges to rent shoes and per game. Bowling alley B charges to re shoes and per game. a. For what numbers of gam
matrenka [14]

The computation shows that the price of each game is $2.5 and the price of shoe rental will be $3.

<h3>How to illustrate the information?</h3>

Fron the information given, the equation will be:

s + 4g = 13

s + 8g = 23

4g = 10

g = 2.5

Therefore, the price of each game is $2.5

The price of shoe rental will be:

s + 4g = 13

s + 4(2.50) = 13

s = 13 - 10.

s = 3

Learn more about computations on:

brainly.com/question/4658834

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1 year ago
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I think this is right

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A 52 foot ladder is set against the side of a house so that it reaches up 48 feet. If Jace
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34.3

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no

8 0
3 years ago
16) Please help with question. WILL MARK BRAINLIEST + 10 POINTS.
Katyanochek1 [597]
We will use the sine and cosine of the sum of two angles, the sine and consine of \frac{\pi}{2}, and the relation of the tangent with the sine and cosine:

\sin (\alpha+\beta)=\sin \alpha\cdot\cos\beta + \cos\alpha\cdot\sin\beta&#10;&#10;\cos(\alpha+\beta)=\cos\alpha\cdot\cos\beta-\sin\alpha\cdot\sin\beta

\sin\dfrac{\pi}{2}=1,\ \cos\dfrac{\pi}{2}=0

\tan\alpha = \dfrac{\sin\alpha}{\cos\alpha}

If you use those identities, for \alpha=x,\ \beta=\dfrac{\pi}{2}, you get:

\sin\left(x+\dfrac{\pi}{2}\right) = \sin x\cdot\cos\dfrac{\pi}{2} + \cos x\cdot\sin\dfrac{\pi}{2} = \sin x\cdot0 + \cos x \cdot 1 = \cos x

\cos\left(x+\dfrac{\pi}{2}\right) = \cos x \cdot \cos\dfrac{\pi}{2} - \sin x\cdot\sin\dfrac{\pi}{2} = \cos x \cdot 0 - \sin x \cdot 1 = -\sin x

Hence:

\tan \left(x+\dfrac{\pi}{2}\right) = \dfrac{\sin\left(x+\dfrac{\pi}{2}\right)}{\cos\left(x+\dfrac{\pi}{2}\right)} = \dfrac{\cos x}{-\sin x} = -\cot x
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3 years ago
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