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Deffense [45]
3 years ago
13

A rectangle has an area of 30 m² and a perimeter of 34 m. What are the dimensions of the rectangle?

Mathematics
1 answer:
romanna [79]3 years ago
7 0
Length is l
width is w
l*w = 30
2l + 2w = 34

You can simplify the second equation to l + w = 17

Factors of 30:
30*1
15*2
10*3
6*5

Try adding each of these factors together, to find out which equals 17

30 + 1 = 31
15 + 2 = 17
10 + 3 = 13
6 + 5 = 11

So the dimensions of the rectangle are 15m * 2m
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3 years ago
A rectangle has a width of 3 units. The rectangle's length is 5 times its width.
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Answer:

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now,

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Answer:

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Step-by-step explanation:

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2 years ago
Find an equation for the line with the given properties. Perpendicular to the line x - 6y = 8; containing the point (4,4) O 1) y
Pepsi [2]

Answer:

Option 3 - y=-6x+28

Step-by-step explanation:

Given : Perpendicular to the line x - 6y = 8; containing the point (4,4).

To Find : An equation for the line with the given properties ?

Solution :

We know that,

When two lines are perpendicular then slope of one equation is negative reciprocal of another equation.

Slope of the equation x - 6y = 8

Converting into slope form y=mx+c,

Where m is the slope.

y=\frac{x-8}{6}

y=\frac{x}{6}-\frac{8}{6}

The slope of the equation is m=\frac{1}{6}

The slope of the perpendicular equation is m_1=-\frac{1}{m}

The required slope is m_1=-\frac{1}{\frac{1}{6}}

m_1=-6

The required equation is y=-6x+c

Substitute point (x,y)=(4,4)

4=-6(4)+c

4=-24+c

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Substitute back in equation,

y=-6x+28

Therefore, The required equation for the line is y=-6x+28

So, Option 3 is correct.

8 0
2 years ago
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