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Lelechka [254]
4 years ago
9

Please help and step by step​

Mathematics
1 answer:
joja [24]4 years ago
4 0

Answer:

240

Step-by-step explanation:

<u>1,600 </u> × <u> 15 </u>

    1        100

Reduce the numbers with greatest common divisor 100

<u>16</u> ×  15

1

Calculate the product; multiply.

<u>240</u>

  1

Any expression divided by 1 remains the same.

240/1 = 240

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Maurinko [17]
It will increase beyond bounds  
8 0
3 years ago
The price of apples at three different stores is shown below. Store R sells apples for $1.20 per pound. Store S sells 4 pounds o
blsea [12.9K]

Answer:

Store T sells apples at the lowest rate

$1.16

Step-by-step explanation:

which of these is a true statemnt

Store R sells apples at the lowest rate

Store T sells apples at the lowest rate

Store s charges a lower rate than Store T

Store t charges the same rate as Store R

Given:

Store R= $1.20 per pound

Store S =$5.00 for 4 pounds

Store T=$3.48 for 3 pounds

Find the price of apple per pound

Store R=1.20 per pound of Apple

Store S=$5.00/4

=$1.25 per pound of Apple

Store T=$3.48/3 pounds

=$1.16 per pound of Apple

From the statements above,

Store T sells apples at the lowest rate

5 0
3 years ago
370 people bought tickets to a fair. Adult tickets were $7 and kids tickets were $3. Total revenue was $1750. Child tickets are
galina1969 [7]

210 children tickets are sold

<em><u>Solution:</u></em>

Let "x" be the number of child tickets sold

Let "y" be the number of adult tickets sold

Cost of 1 adult ticket = $ 7

Cost of 1 child ticket = $ 3

<em><u>Given that 370 people bought tickets to a fair</u></em>

number of child tickets sold + number of adult tickets sold = 370

x + y = 370 ------ eqn 1

<em><u>Total revenue was $1750. Therefore,</u></em>

number of child tickets sold x Cost of 1 child ticket + number of adult tickets sold x Cost of 1 child ticket = 1750

x \times 3 + y \times 7 = 1750

3x + 7y = 1750 ------ eqn 2

<em><u>Let us solve eqn 1 and eqn 2</u></em>

From eqn 1,

x = 370 - y ------- eqn 3

<em><u>Substitute eqn 3 in eqn 2</u></em>

3(370 - y) + 7y = 1750

1110 - 3y + 7y = 1750

4y = 1750 - 1110

4y = 640

<h3>y = 160</h3>

From eqn 3,

x = 370 - 160

<h3>x = 210</h3>

Thus 210 children tickets are sold

7 0
3 years ago
Given a triangle with vertices P(-9,7), Q(-3,7), and R(-3,1), and S is the midpoint of PQ and T is the midpoint of QR, what is t
Natalija [7]
Check the picture below.

so we know S is the midpoint of PQ, and T is the midpoint of QR, thus

\bf ~~~~~~~~~~~~\textit{middle point of 2 points }\\\\&#10;\begin{array}{ccccccccc}&#10;&&x_1&&y_1&&x_2&&y_2\\&#10;%  (a,b)&#10;&P&(~ -9 &,& 7~) &#10;%  (c,d)&#10;&Q&(~ -3 &,& 7~)&#10;\end{array}\quad&#10;%   coordinates of midpoint &#10;\left(\cfrac{ x_2 +  x_1}{2}\quad ,\quad \cfrac{ y_2 +  y_1}{2} \right)&#10;\\\\\\&#10;S=\left( \cfrac{-3-9}{2}~,~\cfrac{7+7}{2} \right)\implies S=(-6,7)\\\\&#10;-------------------------------

\bf ~~~~~~~~~~~~\textit{middle point of 2 points }\\\\&#10;\begin{array}{ccccccccc}&#10;&&x_1&&y_1&&x_2&&y_2\\&#10;%  (a,b)&#10;&Q&(~ -3 &,& 7~) &#10;%  (c,d)&#10;&R&(~ -3 &,& 1~)&#10;\end{array}&#10;\\\\\\&#10;T=\left(\cfrac{-3-3}{2}~,~\cfrac{1+7}{2}  \right)\implies T=(-3,4)

so, what's the distance from S to T?

\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\\\&#10;\begin{array}{ccccccccc}&#10;&&x_1&&y_1&&x_2&&y_2\\&#10;%  (a,b)&#10;&S&(~ -6 &,& 7~) &#10;%  (c,d)&#10;&T&(~ -3 &,& 4~)&#10;\end{array}\\\\\\ &#10;%  distance value&#10;d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}&#10;\\\\\\&#10;ST=\sqrt{[-3-(-6)]^2+[4-7]^2}\implies ST=\sqrt{(-3+6)^2+(4-7)^2}&#10;\\\\\\&#10;ST=\sqrt{3^2+(-3)^2}\implies ST=\sqrt{18}\implies ST=\sqrt{9\cdot 2}&#10;\\\\\\&#10;ST=\sqrt{3^2\cdot 2}\implies ST=3\sqrt{2}

5 0
3 years ago
A cone of day has a radius of 6 cm and a height of 20 cm. What is its volume?
Ludmilka [50]

Answer:

\frac{1}{3}  \times \pi \times  {r }^{2}  \times h \\  \frac{1}{3}  \times 3.14 \times 36 \times 20 \\  \\  = 753.6 {cm}^{3}

either you can write it in terms of π

4 0
3 years ago
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