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kodGreya [7K]
3 years ago
7

Help Me! WITH THIS HARD PROBLEM

Mathematics
2 answers:
Pepsi [2]3 years ago
5 0
Answer 15 is A because when you count each square it goes by two so if it stops in the middle its 1
Fynjy0 [20]3 years ago
4 0
Hope this helps but I think number 14 is C.) on the y axis, and number 15 I think it is either C or D.
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\bf \displaystyle\int~\cfrac{~~\begin{matrix} sin(4x-1) \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~ }{u^2}\cdot \cfrac{du}{-4~~\begin{matrix} sin(4x-1) \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}\implies -\cfrac{1}{4}\int\cfrac{1}{u^2}du\implies -\cfrac{1}{4}\int u^{-2}du \\\\\\ -\cfrac{1}{4}\cdot \cfrac{u^{-2+1}}{-1}\implies \cfrac{1}{4}\cdot u^{-1}\implies \cfrac{1}{4u}\implies \cfrac{1}{4cos(4x+1)}+C

5 0
4 years ago
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mamaluj [8]

Answer:

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