3 years ago

Help Me! WITH THIS HARD PROBLEM

Mathematics

2 answers:

Pepsi [2]3 years ago

5 0

Answer 15 is A because when you count each square it goes by two so if it stops in the middle its 1

Fynjy0 [20]3 years ago

4 0

Hope this helps but I think number 14 is C.) on the y axis, and number 15 I think it is either C or D.

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the bottom of a ladder must be placed 3 feet from a wall the laser is 10 feet long how far above the ground does the ladder touc

kaheart [24]

It would be 7 feet above ground

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3 years ago

In a bag of m&m's there are 5 brown 6 yellow 4 blue 3 green and 2 orange. What's the probability of getting 3 yellow m&m

olasank [31]

There are 5+6+4+3+2=20 m&m's in the bag.
Calculate in how many ways you can choose 3 m&m's from 20:
$_{20} C _3=\frac{20!}{3!(20-3)!}=\frac{20!}{3! \times 17!}=\frac{17! \times 18 \times 19 \times 20}{6 \times 17!}=\frac{18 \times 19 \times 20}{6}=3 \times 19 \times 20= \\
=1140$

There are 6 yellow m&m's.
Calculate in how many ways you can choose 3 m&m's from 6:
$_6 C _3 = \frac{6!}{3!(6-3)!}=\frac{6!}{3! \times 3!}=\frac{3! \times 4 \times 5 \times 6}{3! \times 6}=\frac{4 \times 5 \times 6}{6}=4 \times 5=20$

The probability is the number of ways of choosing 3 m&m's from 6 m&m's divided by the number of ways of choosing 3 m&m's from 20 m&m's.
$P=
\frac{20}{1140}=\frac{20 \div 20}{1140 \div 20}=\frac{1}{57}$

The probability is 1/57.

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3 years ago

Use the scenario to answer the question. Tyrone was asked to write the recursive and explicit formula for the sequence {−4,−7,−1

Anton [14]

The last option: In his recursive formula, he should have the term an−1 instead of −4 to get an=an−1−3.

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3 years ago

a group of 5 friends is out to dinner Each of the friends will order the dinner special and they have a coupon for $10 off the e

scZoUnD [109]

Answer:

TC = 5x -10

Step-by-step explanation: