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o-na [289]
3 years ago
5

How to solve |2x-4|=8

Mathematics
2 answers:
zaharov [31]3 years ago
6 0
Ok... let's break it apart and put it back together.

There's an absolute value... "2x-4" is inside the absolute value. The absolute value of "2x-4" is equal to the value of 8... so find x.

There are TWO cases:

(2x-4)=8
    OR
 -(2x-4)=8 

Now you should be able to solve it. If you can't... well, just ask me below. I can't do ALL the work, can I?
 :P
valentina_108 [34]3 years ago
3 0
|2x - 4| = 8 ⇔ 2x - 4 = -8 or 2x - 4 = 8  |add 4 to both sides

2x = -4 or 2x = 12    |divide both sides by 2

x = -2 or x = 6
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8 0
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Estamate 12871+6281+5146 by first rounding each number to the nearest thousand.
Pie
12,871 rounded to nearest thousand = 13,000.

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5146 rounded to nearest thousand = 5,000.

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4 0
3 years ago
Find the missing number in the factor tree<br><br> for 20 points<br><br> i hope you will help
ELEN [110]

Answer:

see below

Step-by-step explanation:

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We are breaking the numbers into primes

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3 0
2 years ago
Lines AB and BC intersect at point B. Ray BD bisects angle ABC. (4x-24) B (x+6) What is the value of x?
Verizon [17]

If line AB and BC are intersecting at point B and ray BD bisect the angle ABC, then the value of x is 23

The line AB and BC are intersecting at point B.

Ray BD bisect the  angle ABC

∠ABD = x+8 degrees

∠ABD=∠DBC = x+8

Because the ray BD bisect the ∠ABC, so ∠ABD and ∠DBC will be equal

∠ABD+∠DBC= 4x-30 degrees

Because both are vertically opposite angles

Substitute the values in the equation

x+8 + x+8 = 4x-30

2x+16 = 4x-30

2x-4x = -30-16

-2x = -46

x = 23

Hence, if line AB and BC are intersecting at point B and ray BD bisect  the angle ABC, then the value of x is 23

The complete question is

Line AB and BC are intersecting at point B and ray BD bisect the angle ABC. What is the value of x?

Learn more about angle here

brainly.com/question/28451077

#SPJ1

4 0
1 year ago
5x-6_&lt; -5x +16 <br> solve
Olegator [25]

Answer:

haha

Step-by-step explanation:

thanks for the points

4 0
2 years ago
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