Answer:
0.25 rad to the nearest hundredth radian
Step-by-step explanation:
Here is the complete question
Suppose a projectile is fired from a cannon with velocity vo and angle of elevation (theta). The horizontal distance R(θ) it travels (in feet) is given by the following.
R(θ) = v₀²sin2θ/32
If vo=80ft/s what angel (theta) (in radians) should be used to hit a target on the ground 95 feet in front of the cannon?
Do not round any intermediate computations, and round your answer(s) to the nearest hundredth of a radian.
(θ)= ?rad
Solution
R(θ) = v₀²sin2θ/32
If v₀ = 80 ft/s and R(θ) = 95 ft
θ = [sin⁻¹(32R(θ)/v₀²)]/2
= [sin⁻¹(32 × 95/80²)]/2
= [sin⁻¹(3040/6400)]/2
= [sin⁻¹(0.475)]/2
= 28.36°/2
= 14.18°
Converting 14.18° to radians, we have 14.18° × π/180° = 0.2475 rad
= 0.25 rad to the nearest hundredth radian
2g - 2h = b + 4
2g = b + 4 + 2h
g = (b + 4 + 2h) / 2
add the like terms
14x=-3+x
subtract x from both sides
13x=-3
divide both sides by 13
x=-3/13
Answer:
diameter = IJ
radius = KH or IH or JH
chord = LM
length HK = 2
Step-by-step explanation:
if IJ is the diameter and the radius is KH then r must be 2 as the radius is always half the diameter
Answer:
Cluster sample
Step-by-step explanation:
i did it before
