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ser-zykov [4K]
3 years ago
8

A sample of granite contains various oxides of silicon, aluminum, sodium, potassium, calcium, and iron. each of these oxides giv

es the granite a coarse-grained texture. which term or terms could be used to describe this sample of granite? check all that apply. check all that apply. mixture heterogeneous mixture homogenous mixture solution pure chemical substance compound element
Chemistry
1 answer:
Julli [10]3 years ago
4 0
It would have a solubility substance and surface

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compound of aspartame is a dipeptide that is often used as a sugar substitute which functional groups are present
Scrat [10]

Answer:

Carboxyl, primary amine, amide, ester, and phenyl.

Explanation:

The functional groups present in the compound of aspartame are carboxyl, primary amine, amide, ester, and phenyl. Aspartame is an artificial non-saccharide sweetener which is 200 times sweeter than sucrose. This aspartame is commonly used as a sugar substitute in many foods and beverages. It has the trade names such as NutraSweet, Equal, and Canderel.

5 0
3 years ago
Why do we put these three words together in the 'fire triangle'?
bazaltina [42]
The three word of this is to represent what it takes to create and maintain a fire
7 0
3 years ago
An atom has three shells with 3 electrons in the last shell. This atom could be.....
Oksana_A [137]
Since the total amount of valence electrons is 3, it is in group 13 in the periodic table..therefore, it is specified as Boron.✅
4 0
3 years ago
"M" represents a metallic element, the oxide of which has the formula M2O. The formula of the chloride of M is..................
Rus_ich [418]
The formula of the chloride of M will be MCI2.
8 0
3 years ago
An atom (not a hydrogen atom) absorbs a photon whose associated wavelength is 300 nm and then immediately emits photon whose ass
KIM [24]

Answer:

The net energy is 2.196 eV

Explanation:

Basically, the energy of an atom increases when it absorbs a photon. In addition, the wavelength of the emitted photon is longer such that the atom absorbed a net energy in the process.

Using:

ΔE = h*c*(1/λ_{1} - 1/λ_{2})

where:

ΔE is the net energy in eV (electron-volt). 1 eV is equivalent to 1.602*10^{-19} J.

h = 4.135*10^{-15} eVs

c = 3*10^{8} m/s

λ_{1} = 300 nm = 300*10^{-9} m

λ_{2} = 640 nm = 640*10^{-9} m

Thus:

ΔE = 4.135*10^{-15} eVs*3*10^{8} m/s*(\frac{1}{300*10^{-9}m } }-\frac{1}{640*10^{-9}m })

ΔE = 4.135*10^{-15}*3*10^{8}*1.77*10^{6} eV = 2.196 eV

6 0
3 years ago
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