Which important change in electronic devices, such as televisions and computers, is a result of the use of metalloids as semicon
2 answers:
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<u>Answer:</u> The moles of precipitate (lead (II) iodide) produced is moles
<u>Explanation:</u>
To calculate the number of moles for given molarity, we use the equation:
.....(1)
- <u>For lead (II) nitrate:</u>
Molarity of lead (II) nitrate solution = 2.70 M
Volume of solution = 33.0 mL = 0.033 L (Conversion factor: 1 L = 1000 mL)
Putting values in equation 1, we get:
- <u>For NaI:</u>
Molarity of NaI solution = 0.00157 M
Volume of solution = 20.0 mL = 0.020 L
Putting values in equation 1, we get:
For the given chemical reaction:
By Stoichiometry of the reaction:
2 moles of NaI reacts with 1 mole of lead (II) nitrate
So, moles of NaI will react with =
of lead (II) nitrate
As, given amount of lead (II) nitrate is more than the required amount. So, it is considered as an excess reagent.
Thus, NaI is considered as a limiting reagent because it limits the formation of product.
By Stoichiometry of the reaction:
2 moles of NaI produces 1 mole of lead (II) iodide
So, moles of NaI will produce =
of lead (II) iodide
Hence, the moles of precipitate (lead (II) iodide) produced is moles
The structural formula of <span>s-allylcysteine is shown in the picture (top figure). To create its Lewis structure, draw all its bonds between elements. Each single bond contains two electrons. There is an octet rule that must be obeyed by most elements. Each element should be surrounded with 8 electrons. The hydrogen is exempted of this rule. So, there are 4 lone pairs for the S atom, 1 lone pair for the N atom, and 2 lone pairs each for the 2 O atoms.</span>
