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AlladinOne [14]
4 years ago
7

Within the water cycles, where do individual water molecules reside the longest?

Chemistry
2 answers:
insens350 [35]4 years ago
5 0
During the condensation process. 1)Evaporation 2)Condensation 3) Precipitation 4)Accumulation That's the process so I say choice 2. Hope this helps.
solniwko [45]4 years ago
4 0
Condensation and precipitation
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Calculate the number of moles of sodium oxide that should be produced with 6.50 g of sodium react with oxygen gas
mars1129 [50]
First of all write a balanced equation.
4Na + O2 -> 2Na2O
You are starting with a mass of sodium. You need to use sodium’s molar mass. Take this quantity times mole to mole ratio between sodium and sodium oxide to get moles of sodium oxide produced.
.141 moles of sodium oxide produced
4 0
3 years ago
hola genteee ayuda me pueden decir 5 propiedades físicas y 5 propiedades químicas del ácido sulfúrico porfa es urgente !
Alexus [3.1K]

Answer:

La respuesta está en la explicación.

Explanation:

Las propiedades físicas son las visibles y medibles que no afectan químicamente la sustancia en cuestión. Las propiedades químicas hacen alusión a la reactividad de la sustancia:

Propiedades físicas ácido sulfúrico:

Líquido a temperatura ambiente.

Densidad: 1.83g/mL

Punto de fusión: 10°C

Punto de ebullición: 337°C

Índice de refracción: 1.397

Propiedades Químicas:

Ácido Fuerte.

Oxidante Fuerte.

Miscible con el agua reaccionando exotérmicamente.

A temperaturas > 30°C produce vapores azufrados.

Estable en concentraciones menores al 98%

8 0
4 years ago
Four major bahiagrass varieties
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5 0
3 years ago
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During aerobic respiration, electrons travel downhill in which sequence? A) food → citric acid cycle → ATP → NAD+
mina [271]
<span>During aerobic respiration, electrons travel downhill in which sequence?
</span><span>B) food → NADH → electron transport chain → oxygen</span>
7 0
4 years ago
What will the volume of 254 cm3 of gas be at STP if its original temperature is 72.6° C?
juin [17]

Answer:

200.6cm³

Explanation:

Using Charles law equation as follows:

V1/T1 = V2/T2

Where;

V1 = initial volume (cm³)

V2 = final volume (cm³)

T1 = initial temperature (K)

T2 = final temperature (K)

According to the question;

initial volume (V1) = 254cm³

final volume (V2) = ?

Initial temperature (T1) = 72.6°C = 72.6 + 273 = 345.6K

Final temperature (T2) = 273K

V1/T1 = V2/T2

254/345.6 = V2/273

Cross multiply

345.6 × V2 = 273 × 254

345.6V2 = 69342

V2 = 69342 ÷ 345.6

V2 = 200.6cm³

3 0
3 years ago
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