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rjkz [21]
4 years ago
14

How many atoms are in Sodium, Carbon, Hydrogen, Oxygen, Fluorine, Boron, Lithium, Helium, Phosphorus and Sulfur?

Chemistry
1 answer:
vlada-n [284]4 years ago
6 0
Sodium. 11
Carbon. 12
Hydrogen 1
Oxygen 2
Fluuorine. 14
Boron. 5
Lithium. 6
Helium 3
Phosphorus 15
Sulfur 6
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Aluminum metal reacts with aqueous cobalt(II) nitrate to form aqueous aluminum nitrate and cobalt metal. What is the stoichiomet
Lelu [443]

Answer:

the stoichiometric coefficient for cobalt is 3

Explanation:

the unbalanced reaction would be

Co(NO₃)₂+ Al → Al(NO₃)₃ + Co

One way to solve is to build a system of linear equations for each element (or group as NO₃) , knowing that the number of atoms of each element is conserved.

For smaller reactions a quick way to solve it can be:

- First the Co as product and as reactant needs to have the same stoichiometric coefficient

- Then the Al as product and as reactant needs to have the same stoichiometric coefficient

- After that we look at the nitrates . There are 2 as reactants and 3 as products . Since the common multiple is 6 then multiply the reactant by 3 and the product by 2.

Finally the balanced equation will be

3 Co(NO₃)₂+ 2 Al → 2 Al(NO₃)₃ + 3 Co

then the stoichiometric coefficient for cobalt is 3

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4 years ago
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daser333 [38]

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A 64.0 ml volume of 0.25 m hbr is titrated with 0.50 m koh. calculate the ph after addition of 32.0 ml of koh at 25 ∘c.
aleksley [76]
Hello!

The reaction between HBr and KOH is the following:

HBr+KOH→H₂O + KBr

To calculate the amount of HBr left after addition of KOH, you'll use the following equations:

HBr_f=HBr_i-KOH=([HBr]*vHBr)-([KOH]*vKOH) \\  \\ HBr_f=(0,25M*0,64L)-(0,5M*0,32L)=0 mol HBr

That means that after the addition of 32 mL of KOH, there is no HBr left in the solution and the pH should be neutral, close to 7. 

Have a nice day!
3 0
3 years ago
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