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2 years ago

How many moles of oxygen are needed for the complete combustion of 12.6 moles of acetylene?

Chemistry

1 answer:

soldi70 [24.7K]2 years ago

8 0

The moles of oxygen required to completely react with 1-mole acetylene is 2.5 mol.

The moles of reactant and product in a chemical reaction to the whole number ratio is given by the stoichiometric coefficient of the balanced chemical equation.

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Richter Scale.

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3 years ago

A ________ is an electric circuit that produces a magnetic field

aksik [14]

I believe it would be D. Electromagnet. It's been a while since I've done this stuff, tho. Hope this helps!!!! :)

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2 years ago

Carbon dioxide dissolves in water to form carbonic acid, which is primarily dissolved CO2. Dissolved CO2 satisfies the equilibri

lorasvet [3.4K]

Explanation:

The reaction equation will be as follows.

$CO_{2}(aq) + H_{2}O \rightleftharpoons H^{+}(aq) + HCO^{-}_{3}(aq)$

Calculate the amount of $CO_{2}$ dissolved as follows.

$CO_{2}(aq) = K_{CO_{2}} \times P_{CO_{2}}$

It is given that $K_{CO_{2}}$ = 0.032 M/atm and $P_{CO_{2}}$ = $1.9 \times 10^{-4}$ atm.

Hence, $[CO_{2}]$ will be calculated as follows.

$[CO_{2}]$ = $K_{CO_{2}} \times P_{CO_{2}}$

= $0.032 M/atm \times 1.9 \times 10^{-4}atm$

= $0.0608 \times 10^{-4}$

or, = $0.608 \times 10^{-5}$

It is given that $K_{a} = 4.46 \times 10^{-7}$

As, $K_{a} = \frac{[H^{+}]^{2}}{[CO_{2}]}$

$4.46 \times 10^{-7} = \frac{[H^{+}]^{2}}{0.608 \times 10^{-5}}$

$[H^{+}]^{2}$ = $2.71 \times 10^{-12}$

$[H^{+}]$ = $1.64 \times 10^{-6}$

Since, we know that pH = $-log [H^{+}]$

So, pH = $-log (1.64 \times 10^{-6})$

= 5.7

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2 years ago

Why is the mass of the third subatomic particle ignored?

dmitriy555 [2]

Answer: The mass of electrons is mostly ignored because electrons are extremely small compared to neutrons and protons.

Explanation: A proton is about 1,836 times the size of an electron.

On the periodic table, the atomic number for each element can be found. This number is found by measuring the weight of 6.02 x 10^23 atoms of the element in grams. Electrons aren't ignored when finding exact math, but for the sake of simplification high school teachers will generally have you only count the number of protons and neutrons when calculating the mass of atoms.

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1 year ago

A sample of an unknown compound is vaporized at 150.°C . The gas produced has a volume of 960.mL at a pressure of 1.00atm , and

IrinaK [193]

Answer:

34.02 g.

Explanation:

Hello!

In this case, since the gas behaves ideally, we can use the following equation to compute the moles at the specified conditions:

$PV=nRT\\\\n=\frac{1.00atm*0.960L}{0.08206\frac{atm*L}{mol*K}*(150+273)K} =0.0277mol\\\\$

Now, since the molar mass of a compound is computed by dividing the mass over mass, we obtain the following molar mass:

$MM=\frac{0.941g}{0.0277mol} \\\\MM=34.02g/mol$

So probably, the gas may be H₂S.

Best regards!

6 0

3 years ago