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Triss [41]
3 years ago
10

A bag contains 9 marbles: 2 are green, 2 are red, and 5 are blue. Yoko chooses a marble at random, and without putting it back,

chooses another one at random. What is the probability that both marbles she chooses are green? Write your answer as a fraction in simplest form.

Mathematics
1 answer:
VikaD [51]3 years ago
3 0

Answer: 1/36

Step-by-step explanation: To find the probability of picking a green marble and picking another green marble, it's important to understand that once Yoko chooses the first marble, it's not replaced which means that there are fewer marbles in the bag.

This means that the outcome of the first event affects the outcome of the second event which means that these are dependent events.

When finding the probability of two dependent events, we first find the probability of each event and then multiply the probabilities.

Let's first find the probability of choosing one green marble.

Since there are 2 green marbles are 9 total marbles, the probability of choosing a green marble is 2/9.

Next we find the probability of choosing another green marble. Remember that the first marble was not put back in the jar which means that there are 8 total marbles in the bag.

Since there is only 1 green marble left and 8 of them are in the bag, the probability of choosing another green one is 1/8.

Now to find the probability of choosing a green marble, not replacing it, and choosing another green marble, we multiply (\frac{2}{9}) (\frac{1}{8}).

Image provided.

Therefore, the probability of choosing a green marble, not replacing it, and choosing another green marble is 1/36.

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Jordan Pat 6 4/5 yards of pink ribbon and 3 1/4 yards of purple ribbon how much more pink ribbon the purple ribbon did she buy?
evablogger [386]
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8 0
3 years ago
An octagonal swimming pool has a base area of 22 square feet The pool is 3 feet deep How many cubic feet of water can the pool h
LenKa [72]

The pool can hold 65.84 ft³ of water

<u>Explanation:</u>

Given:

Shape of pool = octagonal

Base area of the pool = 22 ft²

Depth of the pool = 3 feet

Volume, V = ?

We know:

Area of octagon = 2 ( 1 + √2) a²

22 ft² = 2 ( 1 + √2 ) a²

\frac{11}{1+\sqrt{2} } = a^2

a² = \frac{11}{2.42}

a² = 4.55

a = 2.132 ft

Side length of the octagon is 2.132 ft

We know:

Volume of octagon = 2(1+\sqrt{2} ) X (a)^2 X h

V = 2(1+\sqrt{2})X (2.132)^2 X 3\\ \\V = 2 ( 2.414) X 4.5454 X 3\\\\V = 65.84 ft^3

Therefore, the pool can hold 65.84 ft³ of water

8 0
3 years ago
Y - (-9) = 8?<br><br> I am confused
Yuki888 [10]

Answer:

y = -1

Step-by-step explanation:

y - ( - 9) = 8

y + 9 = 8

y = 8 - 9

y = -1

- ( - turns to + because you are subtracting a negative number

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

4 0
3 years ago
Read 2 more answers
3. The following sets are not equal - An (BUC) and AU(BnC) Construct a universe U and non-empty sets A, B, and C so that the abo
yarga [219]

Answer:

1.U={1,2,3,4,5}

A={2}

B={2,3}

C={4,5}

2.U={1,2,3,4}

A={1,2}

B={2,3}

C={4}

Step-by-step explanation:

We are given that A\cap (B\cup C) and A\cup (B\cap C)

are different sets

1.We have to construct a universe set U and non empty sets A,B and C so that above set in fact the same

Suppose U={1,2,3,4,5}

A={2}

B={2,3}

C={4,5}

B\cap C=\phi

B\cup C={2,3,4,5}

A\cap (B\cup C)={2}\cap{2,3,4,5}={2}

A\cup (B\cap C)={2}\cup\phi={2}

Hence, A\cap (B\cup C)=A\cup (B\cap C)

2.We have to construct a universe set U and non empty sets A,B and C so that  above sets are in fact different

Suppose U={1,2,3,4}

A={1,2}

B={2,3}

C={4}

B\cap C=\phi

B\cup C={2,3,4}

A\cup (B\cap C)={1,2}\cup \phi={1,2}

A\cap (B\cup C)={1,2}\cap {2,3,4}={2}

Hence, A\cap (B\cup C)\neq A\cup (B\cap C)

3 0
3 years ago
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