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LUCKY_DIMON [66]
4 years ago
11

Cole is working with radioactive particles and has set up a shield made of aluminum for protection. Which of the following will

he be protected from? Only alpha particles and beta particles Only alpha particles Alpha, beta, and gamma particles Only gamma rays

Chemistry
2 answers:
OLga [1]4 years ago
4 0

Answer:

Alpha, beta, and gamma particles

Explanation:

A shield of aluminium can effectively block off any form of radiation be it alpha, beta or gamma particles.

Radiations are products of nuclear reactions. These radiations produced are quite harmful and injurious to life.

A thick and appropriate material must be used to block off these radiations so as to properly interact with them in an advantageous way.

A shield of aluminium, a block of lead and any material with a high thickness and density is appropriate for neutralizing these forms of radiation.

Mademuasel [1]4 years ago
3 0

Answer:

A) Only alpha particles and beta particles

Explanation:

Aluminium effectively blocks alpha and beta particles. However, gamma radiation will still pass through. This means the answer is A.

Attached is a diagram to demonstrate.

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Answer B

Explanation:

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What kind of energy form is the name for the kinetic energy that all particles have?
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4 0
4 years ago
If air has a dry-bulb temperature of 2°C
Allisa [31]

Answer:

The relative humidity is 36%.

Explanation:

Relative humidity is the measure of ratio of actual vapor density to saturated vapor density in a given system. So there are different ways to measure the relative humidity in the atmosphere. One of the common ways is to measure using Psychrometer. In this instrument, two different thermometers are used as measuring device. One of the thermometer measures the humidity in dry air and another in wet air. So the difference of the temperature of dry and wet air bulb will be related to determine the relative humidity percentage. The formula to determine the relative humidity using this method is as below.

Relative humidity=\frac{(e_{w}-[N*(1+0.00115*T_{w}*(T_{d}-T_{w}))])*100}{e_{d} }

Also,

e_{d}=6.112*e^{[\frac{(17.502*T_{d} )}{(240.97+T_{d} )}]}

And,

e_{w}=6.112*e^{[\frac{(17.502*T_{w} )}{(240.97+T_{w} )}]}

Here e =2.718, T_{d} and T_{w} are the temperature at dry bulb and wet bulb temperatures, respectively.

So, the relative humidity after substituting the values of Td = 2 C and Tw = -2 C is 36%.

6 0
3 years ago
What do elements in block have in common?​
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Answer:

The d-block elements are all metals and most have one or more chemically active d-orbital electrons. Because there is a relatively small difference in the energy of the different d-orbital electrons, the number of electrons participating in chemical bonding can vary.

5 0
3 years ago
Read 2 more answers
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