Answer:
65.3658 inches
Step-by-step explanation:
Let X be the height of a woman randomly choosen. We know tha X have a mean of 63.6 inches and a standard deviation of 2.5 inches. For an x value, the related z-score is given by z = (x-63.6)/2.5. We are looking for a value such that
, but,
, i.e.,
is the 76th percentile of the standard normal distribution. So,
,
. Therefore, the height of a woman who is at the 76th percentile is 65.3658 inches.
Answer:
<h2>1.84feet</h2>Step-by-step explanation:
Using the formula for finding range in projectile, Since range is the distance covered in the horizontal direction;
Range
U is the velocity of the arrow
H is the maximum height reached = distance below the bullseye reached by the arrow.
R is the horizontal distance covered i.e the distance of the target from the archer.
g is the acceleration due to gravity.
Given R = 60ft, U = 250ft/s, g = 32ft/s H = ?
On substitution,
Squaring both sides we have;
The arrow will hit the target 1.84feet below the bullseye.