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larisa86 [58]
3 years ago
12

Kevin is riding his bike on a 10 1/8 mile bike path. He has covered the first first 5 3/4 miles already. How many miles does he

have left to ride?

Mathematics
2 answers:
Misha Larkins [42]3 years ago
5 0
He has 4.37 miles left. 10.125-5.75= 4.375
Elis [28]3 years ago
4 0
The answer is 4 and 3/8, because if you subtract 5 3/4 from 10 1/8, you'll get your answer: 4 3/8. Hope this helps, and good luck!!
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4k + 15 greater than -2k + 3
ioda

Answer:

k>-2

Step-by-step explanation:

4k+15>-2k+3

4k-(-2k)+15>3

4k+2k+15>3

6k+15>3

6k>3-15

6k>-12

k>-12/6

k>-2

8 0
3 years ago
Charlie has 5 times as many stamps as Ryan. They have 1608 stamps in all. How many more stamps does Charlie have than Ryan?
Aloiza [94]
Charlie has 321.6 more stamps
6 0
3 years ago
what is the quotient 5-x/x^2 3x-4 divided by x^2-2x-15/x^2 5x 4 in simplifed form state any restrictions on the varible
zheka24 [161]

The quotient when \frac{5-x}{x^2+3x-4} /\frac{x^2-2x - 15}{x^2+5x+4} in simplified form is \frac{-(x+1)}{(x-1)(x+3)}

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

Given that equation:

\frac{5-x}{x^2+3x-4} /\frac{x^2-2x - 15}{x^2+5x+4}

=\frac{5-x}{(x+4)(x-1)} /\frac{(x-5)(x+3)}{(x+4)(x+1)} \\\\=\frac{5-x}{(x+4)(x-1)} * \frac{(x+4)(x+1)}{(x-5)(x+3)}\\\\\frac{-(x-5)}{(x+4)(x-1)} * \frac{(x+4)(x+1)}{(x-5)(x+3)}\\\\=\frac{-(x+1)}{(x-1)(x+3)}

The quotient when \frac{5-x}{x^2+3x-4} /\frac{x^2-2x - 15}{x^2+5x+4} in simplified form is \frac{-(x+1)}{(x-1)(x+3)}

Find out more on equation at: brainly.com/question/2972832

#SPJ1

8 0
2 years ago
HELP FAST I WILL MARK AS BRAINLIEST.
vodka [1.7K]

Answer:

  • s = 1/3(a + b + c + 16)

Step-by-step explanation:

<h3>Given</h3>
  • If (s -a) = 5cm, (s -b) = 10cm, (s -c) = 1cm
  • s = ?
<h3>Solution</h3>

<u>Add up the 3 equations and solve for s:</u>

  • s - a + s - b + s - c = 5 + 10 + 1
  • 3s = 16 + a + b + c
  • s = 1/3(a + b + c + 16)
7 0
3 years ago
There are 1,000 fish in a lake. Each year the population declines by 15%, but afterward, the lake is restocked with 500 aditiona
KatRina [158]
We begin with 1,000 fish in a lake.
Each year the population declines to 15%
Then they put back 500 fish in the lake.

The equation: (1000 * .85) +500
4 0
3 years ago
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