The distance travelled is 10 m
The velocity gained at the end of the time is 2 m/s
<h3>Motion</h3>
From the question, we are to determine distance travelled and the velocity gained
From one of the equations of motion for <u>linear motion</u>, we have that
S = ut + 1/2at²
Where S is the distance
u is the initial velocity
t is the time taken
and a is the acceleration
First, we will calculate the acceleration
Using the formula,
F = ma
Where F is the force
m is the mass
and a is the acceleration
∴ a = F/m
Where F is the force
and a is the acceleration
From the given information,
F = 50 N
m = 250 kg
Putting the parameters into the equation,
a = 50/250
a = 0.2 m/s²
Thus,
From the information,
u = 0 m/s (Since the object was initially at rest)
t = 10 s
S = 0(t) + 1/2(0.2)(10)²
S = 10 m
Hence, the distance travelled is 10 m
For the velocity
Using the formula,
v = u + at
Where v is the velocity
v = 0 + 0.2×10
v = 2 m/s
Hence, the velocity gained at the end of the time is 2 m/s
Learn more on Motion here: brainly.com/question/10962624
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Answer:
5a
Step-by-step explanation:
Solution
verified
Verified by Toppr
We have x
3
−ax
2
+6x−a
Apply remainder theorem
x−a=0
x=a
Put x=a in equation.
(a)
3
−a(a)
2
+6a−a
=a
3
−a
3
+6a−a
=6a−a
=5a
Then reminder is 5a
Answer: -13, -15
Step-by-step explanation:
If x is the smallest integer, then:
x + (x + 1) + (x + 2) = x - 27
3x + 3 = x - 27
2x = -30
x = -15
Integers: -15, -14, -13
The answer you are looking for is B. 15
