32.5 % of lab are wireless devices
<em><u>Solution:</u></em>
Given that there was a total of 30 computers and the computer lab is removing 3 broken computers and adding 13 wireless devices
Now we can first find out total number of computers and devices in lab
total number of computers and devices in lab = 30 computers - 3 + 13 wireless devices
total number of computers and devices in lab = 30 - 3 + 13 = 40
So there are 40 computers and wireless devices in lab
<em><u>To find: what percent of the lab are wireless devices</u></em>
So we have to find what percent of 40 is 13
Let "a" be the required percent
a % of 40 = 13
32.5 % of of lab are wireless devices
Hey there!!
Given :
The total cost for 2 pairs of pants and 5 shirts is $61.
The total cost for 3 pairs of paints and 4 shirts is $67.
<em>Let's take the cost for each pair of paints as 'p' and the cost for each shirt as 's'. </em>
Now, let's get these into an equation.
<em>Peter's equation</em> :
... 2p + 5s = 61
<em>Jessica's equation : </em>
...3p + 4s = 67
......................................................................................................
2p + 5s = 61 --- (1)
3p + 4s = 67 --- (2)
Multiply the first equation with 3 and the second equation with 2.
6p + 15s = 183
6p + 8s = 134
S<em>ubtract both the equations - </em>
... 7s = 49
Divide both sides with 7.
... s = 7
<u><em>Hence, the cost of each shirt is $7. </em></u>
Hope my answer helps!!
A. 36/a
B. 55-b
C.18+c
D.49d
E.e/62
W=mg
<span>Where: </span>
<span>Weight = mass * acceleration due to gravity </span>
<span>So let's say I want to work out my weight on the moon. I know I weigh about 70kg (which would be N), but I can't use that figure for the calculation on the moon. That is what I weigh on Earth, so let's look at the equation... </span>
<span>70kg = mass * 9.81m/s^2 </span>
<span>Where 9.81m/s^2 is the acceleration due to gravity on the surface on the earth. I want to get rid of that, so let's work out my mass by division; </span>
<span>70/9.81 = 7.14kg </span>
<span>I googled the acceleration of gravity on the Moon, which was = 1.6m/s^2 </span>
<span>Let's use that in the same equation W=mg </span>
<span>W = 7.14kg * 1.6m/s^2 = 11.42N
</span><span>On the Moon, you would weigh approximately one sixth of your weight on Earth, so if your bathroom scales tell you you weigh 120 pounds, there you would weigh 20 pounds.
</span>
<span>Moon`s gravitational pull is about one-sixth to the gravitational pull on earth hence weight on moon is about one-sixth of the weight on earth.</span>
Length of the rectangle is 8 units
Step-by-step explanation:
- Step 1: Find the length, let width be x.
Area of the rectangle = 48 units
Length = x + 2
⇒ Area = Length × Breadth
48 = x (x + 2)
48 = x² + 2x
x² + 2x - 48 = 0
x² + 8x - 6x + 48 = 0 (Product Sum rule to factorise)
x(x + 8) - 6(x + 8) = 0
(x - 6)(x + 8) = 0
⇒ x = 6, -8 (negative value is neglected)
∴ x = 6
x + 2 = 8
