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4 years ago

Subtract. 1 2/5−(−3/5) Enter your answer, in simplest form, in the box.

Mathematics

2 answers:

bija089 [108]4 years ago

6 0

Answer:

Step-by-step explanation:

1 2/5−(−3/5)

2/5- -3/5=1

1+1=2

Hope this helps.

mars1129 [50]4 years ago

5 0

Answer:

3/5

Step-by-step explanation:

you need to subtract the two fractions then you can divide them by 2 to make them in their simplest form!

HOPE THIS HELPS!!!

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Graph the linear inequality: 2x + 3y = 12, by creating a t-chart to plot the points. Shade by

Crazy boy [7]

Answer:

See explanation

Step-by-step explanation:

Assuming the given inequality is $2x+3y\le12$

Then the corresponding linear equation is $2x+3y=12$

When x=0, we have $2*0+3y=12$

$\implies 3y=12\implies y=4$

When y=0, we have $2x+3*0=12$

$\implies 2x=12\implies x=6$

The T-table is:

0 | 4

6 | 12

We plot this points and draw a solid straight line as shown in the attachment.

Now let us test the origin: (0,0) by plugging x=0 and y=0 into the inequality.

$2*0+3*0\le12$

$0\le12$ ....This is true so we shade the lower half plane as shown in the attachment.

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3 years ago

Company A charges a base rate of $5 per month, plus 4 cents per minute that you are on the phone. Company B charges a base rate

Afina-wow [57]

...........................

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3 years ago

4. Allison's vegetable garden is in shape of rectangle with an area of 10 feet^2. The width of

inna [77]

Answer:

33333

Step-by-step explanation:

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3 years ago

Inverse of the function f(x) = 2x + 5?

andrew-mc [135]

Answer:

$y^{-1} =\frac{1}{2} x-\frac{5}{2}$

Step-by-step explanation:

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3 years ago

Read 2 more answers

A random sample of 70 printers discovered that 25 of them were being used in small businesses. find the 95% limit for the popula

kvasek [131]

Answer:

The sample proportion of printers used in small business is:

$\hat{p}=\frac{25}{70}=0.3571$

The 95% confidence interval for the population proportion of printers that are used in small businesses is:

$\hat{p} \pm z_{\frac{0.05}{2}} \sqrt{\frac{\hat{p}(1-\hat{p})}{n} }$

Where:

$z_{\frac{0.05}{2}}=1.96$ is the critical value at 0.05 significance level

$\therefore 0.3571 \pm 1.96 \sqrt{\frac{0.3571(1-0.3571)}{70} }$

$0.3571 \pm 0.1122$

$\left ( 0.3571 - 0.1122, 0.3571 + 0.1122 \right)$

$\left(0.245,0.469 \right)$

Therefore, the 95% confidence interval for the population proportion of printers that are used in small businesses is (0.245 , 0.469)

7 0

3 years ago