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Novay_Z [31]
3 years ago
12

if tanA= -1/7 and tanB= 3/4, where A is abtuse and B is acute, Find without using tables the value of A-B (ans/135)​

Mathematics
1 answer:
Damm [24]3 years ago
5 0

Answer:

A - B =  135 \degree

Step-by-step explanation:

Recall the trigonometric identity:

\tan(A - B)=\frac{\tan A-\tan B}{1+\tan A \tan B}

We substitute;

tan A=-1/7 and tan B=3/4

\tan(A - B)=\frac{ -  \frac{1}{7} - \frac{3}{4} }{1 -  \frac{1}{7}  \times  \frac{3}{4} }

\tan(A - B) =  - 1

This implies that,

A - B =  { \tan}^{ - 1} ( - 1)

A - B =  { \tan}^{ - 1} (  1) + 90

A - B = 45+ 90

A - B =  135 \degree

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