Question

(-4,-6) and (3,-7) find the distance between each pair of points

Answer 1

Answer:

$5\sqrt{2}\approx 7.07$ units.

Step-by-step explanation:

We have been given coordinates of two points. We are asked to find the distance between both points.

We will use distance formula to solve our given problem.

$D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Let point $(-4,-6)=(x_1,y_1)$ and point $(3,-7)=(x_2,y_2)$.

$D=\sqrt{(3-(-4))^2+(-7-(-6))^2}$

$D=\sqrt{(3+4)^2+(-7+6)^2}$

$D=\sqrt{(7)^2+(-1)^2}$

$D=\sqrt{49+1}$

$D=\sqrt{50}$

$D=\sqrt{25*2}$

$D=5\sqrt{2}$

$D=7.07$

Therefore, the distance between both points is $5\sqrt{2}\approx 7.07$ units.

Answer 2

Answer:

$5\sqrt{2}$

Step-by-step explanation:

distance between two points:

$d = \sqrt{(x_{2}-x_{1})^{2}+ (y_{2}-y_{1})^{2}}$

we have:

(-4, -6), (3, -7)

$x_{1} = -4$

$y_{1} =-6$

$x_{2} = 3$

$y_{2} =-7$

so we have:

$d =\sqrt{(3-(-4))^{2}+ (-7-(-6))^{2}}\\\\d =\sqrt{(7)^{2}+ (-1)^{2}}\\\\d = \sqrt{49+ 1}\\\\d=\sqrt{50}\\\\d=5\sqrt{2}$