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natulia [17]
3 years ago
10

Plz help scientific notation​

Mathematics
1 answer:
Dominik [7]3 years ago
4 0

a. 122/5

b.

\pi

and then 3.14

c. 3.14 has a definite end while pi does not

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Please help me! i’m really confused on this because i keep getting -5 outside the thing
Leona [35]

Answer: D.

Step-by-step explanation: First you find the common factor, which is 5x³y. Then you write in parenthesis what's left over from each term. So  the answer should look like: 5x³y(-3x⁵-4z+9).

4 0
1 year ago
Please help me I would really appreciate it.
Karo-lina-s [1.5K]

Given:

\overline{AB}\cong \overline {CD},\overline{BC}\cong \overline {DA}

To prove:

\Delta CDA\cong \Delta ABC

Proof:

In \Delta CDA\text{ and } \Delta ABC,

\overline{AB}\cong \overline {CD} because Given

\overline{BC}\cong \overline {DA} because Given

\overline{AC}\cong \overline {AC} because Reflexive property.

Corresponding sides of both triangles are congruent. So,

\Delta CDA\cong \Delta ABC because SSS

Therefore, the required missing values are: Given, \overline{BC}\cong \overline {DA}, Reflexive property ,\Delta CDA\cong \Delta ABC, SSS respectively.

5 0
2 years ago
What's the solution to the inequality ??
stealth61 [152]
X<-2

hope this helped! 

4 0
3 years ago
Read 2 more answers
Suppose Y varies directly with X and Y equals 10 when X equals -3 what direct variation equation relates XNY what is the value o
xeze [42]

Answer:

Expression: Y = -10/3 X

Y = 10/3

Step-by-step explanation:

If Y varies directly as X, then;

Y∝X

Y = kX

k is the constant of variation

If Y = 10 and X = -3

10 = -3k

k = -10/3

Substitute k = -10/3 into the expression Y = kX

Y = -10/3 X

This gives the required expression

To get the value of Y when X = -1

Recall that Y = kX

Y = -10/3 (-1)

Y = 10/3

Hence the value of Y is 10/3

8 0
3 years ago
Rewrite x2 − 6x + 7 = 0 in the form (x − a)2 = b, where a and b are integers, to determine the a and b values.
Setler79 [48]

Answer:

Therefore values of a and b are

a=3\ and\ b = 2

Step-by-step explanation:

Rewrite x^{2}-6x+7=0 in the form

(x-a)^{2}=b

where a and b are integers,

To Find:

a = ?

b = ?

Solution:

x^{2}-6x+7=0 ..............Given

Which can be written as

x^{2}-6x=-7

(\frac{1}{2} coefficient\ of\ x)^{2}=(\frac{1}{2}\times -6)^{2}=9

Adding half coefficient of X square on both the side we get

x^{2}-6x+9=-7+9=2 ...................( 1 )

By identity we have (A - B)² =A² - 2AB + B²

Therefore,

x^{2}-6x+9=x^{2}-2\times 3\times x+3^{2}=(x-3)^{2}

Substituting in equation 1 we get

(x-3)^{2}=2

Which is in the form of

(x-a)^{2}=b

On comparing we get

a = 3 and b = 2

Therefore values of a and b are

a=3\ and\ b = 2

4 0
3 years ago
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