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3 years ago

-38 = -2(-43d - 24) d=

Mathematics

1 answer:

Gnom [1K]3 years ago

5 0

To develop a molecular clock, you need to find which of the following?

a sequence of molecules

the rate at which changes occur in a type of molecule

how much total change has occurred in a type of molecule from two different species

how many molecules a species hasAnswer:

To develop a molecular clock, you need to find which of the following?

a sequence of molecules

the rate at which changes occur in a type of molecule

how much total change has occurred in a type of molecule from two different species

how many molecules a species has

Step-by-step explanation:

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The average weekly salary of two employees is $5350. One makes $250 more than the other. Find their salaries.

nataly862011 [7]

Answer:

Step-by-step explanation:

7 0

2 years ago

Addie walked 2 1/2 miles in 45 minutes. Suzie covered 2 2/5 miles in 2/3 of an hour.

N76 [4]

Answer:

Suzie's speed was 3.6 mph

Step-by-step explanation:

we know that

The speed is equal to divide the distance by the time

Let

s ----> the speed in mph (miles per hour)

x ----> the distance in miles

y ----> the time in hours

$s=\frac{x}{y}$

Find Suzie's speed

we have

$x=2\frac{2}{5}\ mi$

$y=\frac{2}{3}\ h$

substitute

$s=2\frac{2}{5}:\frac{2}{3}$

Convert mixed number to an improper fraction

$2\frac{2}{5}=2+\frac{2}{5}=\frac{2*5+2}{5}=\frac{12}{5}$

substitute

$s=\frac{12}{5}:\frac{2}{3}=\frac{36}{10}=3.6\ mph$

3 0

3 years ago

Gavin agrees to buy a 6 month package deal of monthly gym passes, and in turn receives a 15% discount. Write an algebraic expres

dolphi86 [110]

15% off means 85% on so I would use .85x · 6 = total monthly cost to represent this problem. The dot represents times (I did not want to confuse things by using x)

Other ways to express this:

6 x .85x
6(.85x)
.85x (6)

4 0

3 years ago

Read 2 more answers

At the beginning of year 1, Sam invests $700 at an annual compound interest

Aleksandr-060686 [28]

at the beginning of year 4, only 3 years have elapsed, the 4th year hasn't started yet, since it's at the beginning, so at the beginning of year 4 we can say only 4-1 years have elapsed.

$~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$700\\ r=rate\to 5\%\to \frac{5}{100}\dotfill &0.05\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=\textit{elapsed years}\dotfill &3 \end{cases}$

$A=700\left( 1 + \frac{0.05}{1} \right)^{1\cdot 3}\implies A = 700(1+0.05)^3\implies A(4)=700(1+0.05)^{4-1} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill A(n)=700(1+0.05)^{n-1}~\hfill$

6 0

2 years ago

Need help with this question

Alex787 [66]

$y = \frac{4}{3} x + 8$

6 0

3 years ago