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tekilochka [14]
3 years ago
6

Biologists notice an alarming trend in the walleye population in Lake Erie. Despite annual restocking rates of 2 million fish, t

he population is decreasing by 15% each year. They estimate the walleye population was 26 million at the beginning of the current year. Write a sequence to represent the population for the first 4 years. (remember the restocking amount)
Is this sequence geometric or arithmetic? How do you know?



Walleye populations are considered to be in a rehabilitation state when they are between 15 and 20 million. In what year will the population reach this level? In addition to a harvest restriction, what intervention could be used?



What will the population of walleye be in year 8?


Using the formula the sum of the population for the first 10 years?
Mathematics
1 answer:
JulsSmile [24]3 years ago
5 0

Answer:

f(x) = 26000000(.85)^x + 2,000,000

f(1) = 26,000,000

f(2) = 24100000

f(3) = 22485000

f(4) = 21112250

Geometric, it is going down by a %, not a fixed number

Year 5, less pollution

f(8) = 9,084,753.65

Step-by-step explanation:

f(2) = 26,000,000 (.85)^2 + 2,000,000

f(2) = 24100000

f(3) = 26,000,000 (.85)^3 + 2,000,000

f(3) = 22485000

f(4) = 26,000,000(.85)^4 + 2,000,000

f(4) = 21,112,250

f(8) = 26,000,000(.85)^8 + 2,000,000

f(8) = 9,084,753.65

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Given:

The point, (4, -3)

The line,

y=\frac{1}{2}x+5

To find an equation in slope-intercept form for the line that passes through (4,-3) and is parallel to the given line:

The slope of the line is,

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Since the given line is parallel to the new line, so the slope will be same for the both.

Using the point-slope formula,

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\begin{gathered} y-(-3)=\frac{1}{2}(x-4) \\ y+3=\frac{1}{2}x-2 \\ y=\frac{1}{2}x-2-3 \\ y=\frac{1}{2}x-5 \end{gathered}

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2 years ago
Remember to show work and explain. Use the math font.
MrMuchimi

Answer:

\large\boxed{1.\ f^{-1}(x)=4\log(x\sqrt[4]2)}\\\\\boxed{2.\ f^{-1}(x)=\log(x^5+5)}\\\\\boxed{3.\ f^{-1}(x)=\sqrt{4^{x-1}}}

Step-by-step explanation:

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