Answer: 
Explanation:
We have this concentration in units of 
:
And we need to express it in 
, knowing:
Hence:
Answer:
angular frequency is 209439.51 rad/sec
maximum displacement is 0.010504 m
Explanation:
Given data
mass = 2.3 × 10^-20 kg
period = 3.0 × 10^-5 s
maximum speed = 2.2 × 10^3 m/s
to find out
the angular frequency and maximum displacement
solution
we know angular frequency formula that is
angular frequency = 2 π / period
put here period value we get angular frequency
angular frequency = 2 π / 3.0 × 10^-5
angular frequency is 209439.51 rad/sec
maximum displacement formula is
speed = angular frequency × maximum displacement
put all value and we get maximum displacement
maximum displacement = 2.2 × 10^3 / 209439.51
maximum displacement is 0.010504 m
Answer:
Explanation:
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Answer: B
Explanation:
Given that an object of mass 2 kg starts from rest and is allowed to slide down a frictionless incline so that its height changes by 20 m.
The parameters given from the question are:
Mass M = 2kg
Height h = 20m
Let g = 9.8m/s^2
At the bottom of the incline plane, the object will experience maximum kinetic energy.
From conservative of energy, maximum K.K.E = maximum P.E
Maximum P.E = mgh
Maximum P.E = 2 × 9.8 × 20 = 392 J
But
K.E = 1/2mv^2
Substitute the values of energy and mass into the formula
392 = 1/2 × 2 × V^2
V^2 = 392
V = sqrt( 392 )
V = 19.8 m/s
V = 20 m/s approximately
