Hi there!
To find the appropriate force needed to keep the block moving at a constant speed, we must use the dynamic friction force since the block would be in motion.
Recall:
The normal force of an object on an inclined plane is equivalent to the vertical component of its weight vector. However, the horizontal force applied contains a vertical component that contributes to this normal force.
We can plug in the known values to solve for one part of the normal force:
N = (1)(9.8)(cos30) + F(.5) = 8.49 + .5F
Now, we can plug this into the equation for the dynamic friction force:
Fd= (0.2)(8.49 + .5F) = 1.697 N + .1F
For a block to move with constant speed, the summation of forces must be equivalent to 0 N.
If a HORIZONTAL force is applied to the block, its horizontal component must be EQUIVALENT to the friction force. (∑F = 0 N). Thus:
Fcosθ = 1.697 + .1F
Solve for F:
Fcos(30) - .1F = 1.697
F(cos(30) - .1) = 1.697
F = 2.216 N
Answer:
yeah I'm Pretty sure it's b
Answer:
94.28 cm
Explanation:
The formula for elastic potential energy is given as;
PEel = 1/2 *k*x² where x is the displacement, k is the spring constant
Given
PEel = 110 J, k= 350 N/m then find x
PEel = 1/2 *k*x²
110 = 1/2 * 350 * x²
110 = 175 x²
110/175 = x²
0.6286=x²
√0.6286 =x
0.7928 m = x
79.28 cm = x
New length of spring = 15 cm + 79.28 cm = 94.28 cm
You've managed somehow to post the mirror image of the circuit diagram, including the numbers and values of the resistors. I'm curious to know how you did that.
The three resistors at the left end of the diagram are 3Ω , 2Ω , and 1Ω all in series. They behave like a single resistor of (3+2+1) = 6Ω .
That 6Ω resistor is in parallel with the 2Ω drawn vertically in the middle of the diagram. That combination acts like a single resistor of 1.5Ω in that position.
Finally, we have that 1.5Ω resistor in series with 1Ω and 4Ω . That series combination behaves like a single resistor of <em>6.5Ω</em> across the battery V.
Answer:
50.2 meters
Explanation:
When an object falls, it goes a distance d in time t according to the formula:
d is the distance in meter, g is the acceleration due to gravity with the value of 9.8
, t is the time in seconds
Therefore, 
d= 50.176 ≈ 50.2m
