Answer:
2x -3y =1 and 3x-2y= 4 has
Step-by-step explanation:
The pair of linear equations 2x-3y=1 and 3x-2y=4 has one unique solution. , then it has a unique solution other wise not. Since , , it means the pair of linear equations has only one unique solution. Hence, the pair of linear equations 2x-3y=1 and 3x-2y=4 has only one unique solution.
a1/a2= 2/3
b1/b2= 3/-2 (-) cancle so it remains
c1 / c2 = 1/4
a1/a2 = b1/b2 not equal to c1/c2 as no solution
Step-by-step explanation:
Firstly, we have to find m∠J.
Since all the angles of a Δ equal 180°, angles J, L, and K should have a sum of 180°.
So,
m∠J + m∠L + m∠K = 180°
The diagram shows us that ∠L = 49° and ∠K = 90°, so we plug in those numbers in the equation.
m∠J + 49° + 90° = 180°
Then we simplify
m∠J + 139° = 180°
Subtract 139° to both sides
∠J = 41
Now the other angles.
Since ΔJKL ~ ΔRST, then ∠J ≅ ∠R, ∠K ≅ ∠S, and ∠L ≅ ∠T
Meaning, m∠J = m∠R, m∠K = m∠S, and m∠L = m∠T
Since we know m∠J = 41°, m∠K = 90°, and m∠L = 49° we could plug those in so...
41° = m∠R , 90° = m∠S , and 49° = m∠T
A = 90 degrees
B = 50 degrees
D = 140 degrees
E = 40 degrees
HOPE THIS HELPS!
