Step-by-step explanation:
I assume that "ground" is at 0 ft height. which is in an actual scenario not airways the case.
y = -16x² + 64x + 89
shows us that the tower is 89 ft tall (the result for x = 0, at the start).
anyway, if the original assumption is correct, then we need to solve
0 = -16x² + 64x + 89
the general solution for such a quadratic equation is
x = (-b ± sqrt(b² - 4ac))/)2a)
in our case
a = -16
b = 64
c = 89
x = (-64 ± sqrt(64² - 4×-16×89))/(2×-16) =
= (-64 ± sqrt(4096 + 5696))/-32 =
= (-64 ± sqrt(9792))/-32
x1 = (-64 + 98.95453501...)/-32 = -1.092329219... s
x2 = (-64 - 98.95453501...)/-32 = 5.092329219... s
the negative solution for time is but useful here (it would be the time calculated back to ground at the start).
so, x2 is our solution.
the rocket hits the ground after about 5.09 seconds.
Answer:
3600000
Step-by-step explanation:
5000000*.28 = 1400000
5000000-1400000 = 3600000
Answer:
59
Step-by-step explanation:
We know that all the angles must add up to 180
so we have
38+2b-20+b-15=180
solve for b
3b+3=180
3b=177
b=59
Answer:
3 values
Step-by-step explanation:
2x +8 <22 and 3x >9
Solve the two inequalities separately and then put them back together
2x +8 <22
Subtract 8 from each side
2x +8-8 <22 -8
2x < 14
Divide by 2
2x/2 < 14/2
x < 7
Then solve the second inequality
3x>9
Divide by 3
3x/3>9/3
x >3
Putting them back together
x>3 and x < 7
Since it has to be an integer
4,5,6 are possible choices
3 values
