All categories

2 years ago

Bonus Question:

Mathematics

1 answer:

KengaRu [80]2 years ago

4 0

Answer:

I'm not sure what to do not doing this in skl

You might be interested in

A box contains 5 red balls, 6 white balls and 9 black balls. Two balls are drawn at

valina [46]

Answer:

$P(Same)=\frac{61}{190}$

Step-by-step explanation:

Given

$Red = 5$

$White = 6$

$Black = 9$

Required

The probability of selecting 2 same colors when the first is not replaced

The total number of ball is:

$Total = 5 + 6 + 9$

$Total = 20$

This is calculated as:

$P(Same)=P(Red\ and\ Red) + P(White\ and\ White) + P(Black\ and\ Black)$

So, we have:

$P(Same)=\frac{n(Red)}{Total} * \frac{n(Red) - 1}{Total - 1} + \frac{n(White)}{Total} * \frac{n(White) - 1}{Total - 1} + \frac{n(Black)}{Total} * \frac{n(Black) - 1}{Total - 1}$

<em>Note that: 1 is subtracted because it is a probability without replacement</em>

$P(Same)=\frac{5}{20} * \frac{5 - 1}{20- 1} + \frac{6}{20} * \frac{6 - 1}{20- 1} + \frac{9}{20} * \frac{9- 1}{20- 1}$

$P(Same)=\frac{5}{20} * \frac{4}{19} + \frac{6}{20} * \frac{5}{19} + \frac{9}{20} * \frac{8}{19}$

$P(Same)=\frac{20}{380} + \frac{30}{380} + \frac{72}{380}$

$P(Same)=\frac{20+30+72}{380}$

$P(Same)=\frac{122}{380}$

$P(Same)=\frac{61}{190}$

4 0

2 years ago

Pretty easy

Gnom [1K]

$63.2 80% of 79 = 63.2

5 0

3 years ago

A polynomial is to be constructed that has 9 turning points. What is the minimum degree of the polynomial?

Ganezh [65]

A polynomial with 9 turning points has a power of 10. It must have one more power than the number of turning points.

8 0

3 years ago

................................................................................................................................

katovenus [111]

Let me know if you need help with anything thanks

5 0

2 years ago

What is the area of the cross section AFGD?

hjlf

Answer: The area is $15in^2$

Step-by-step explanation:

The cross section AFGD is a rectangle. Then, its area can be calculated with this formula:

$A=l*w$

Where:

"A" is the area of the rectangle.

"l" is the lenght of the rectangle.

"w" is the width of the rectangle.

Then, from the figure, you can identify that the dimensions of the rectangle AFGD are:

$l=5in\\w=3in$

Therefore, you can substitute these values into the formula $A=l*w$ to find the area of the cross section AFGD. Then, you get:

$A=(5in)(3in)\\A=15in^2$

3 0

2 years ago

Read 2 more answers