Use the formula d=rt to find the distance a long distance runner can run at a rate of 9 1/2 miles per hour for time of 1 3/4 hou
2 answers:
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As far as I can make out this one.
the bunker is a 3D object, it has a height, with and length, however we're only concerned with the 2D front face, which has a length and width only.
we know the x-axis is the ground level, so the y-axis must be the scale for the length.
if we can find, using the provided model, the x-intercepts, namely where the x-axis gets touched, we can just get the distance between them and that's the ground level width.
keeping in mind that when the graph touches the x-axis, an x-intercept, "y" is 0.
now, the distance from (-72, 0) and (72, 0) is just 72 +72, or 144.
the bunker is a 3D object, it has a height, with and length, however we're only concerned with the 2D front face, which has a length and width only.
we know the x-axis is the ground level, so the y-axis must be the scale for the length.
if we can find, using the provided model, the x-intercepts, namely where the x-axis gets touched, we can just get the distance between them and that's the ground level width.
keeping in mind that when the graph touches the x-axis, an x-intercept, "y" is 0.
now, the distance from (-72, 0) and (72, 0) is just 72 +72, or 144.
Answer:Increasing in x∈(0,π/4)∪(5π/4,2π) decreasing in(π/4,5π/4)
Step-by-step explanation:
given f(x) = sin(x) + cos(x)
f(x) can be rewritten as
Using these result in equation a we get
f(x) =
Now we know that for derivative with respect to dependent variable is positive for an increasing function
Differentiating b on both sides with respect to x we get
f '(x) =
where x∈(0,2π)
we know that cox(x) > 0 for x∈[0,π/2]∪[3π/2,2π]
Thus for cos(π/4+x)>0 we should have
1) π/4 + x < π/2 => x<π/4 => x∈[0,π/4]
2) π/4 + x > 3π/2 => x > 5π/4 => x∈[5π/4,2π]
from conditions 1 and 2 we have x∈(0,π/4)∪(5π/4,2π)
Thus the function is decreasing in x∈(π/4,5π/4)