Answer:
120°
Step-by-step explanation:
I think its correct
Answer:
(a) The population after 15 years is 2678.
(b)Therefore the population P(t) at any time t>0 is

Step-by-step explanation:
Given that,
The population grew at a rate of

Integrating both sides



[ c is integration constant]



When t=0 , P(0)= 260



Therefore the population P(t) at any time t>0 is

To find the population after 15 years, we need to plug t=15 in the above expression.

≈2678
The population after 15 years is 2678.
If $4000 is the principal, compounded annually at 6%per annum for five years, then-
Amount=principal *(1+rate/100)^5
=4000*(1+6/100)^5
=4000*(53/100)^5
=5352.90
Therefore, Compound Interest =5352.90-4000
=$1352.90
Please recheck the calculation.
The formula is
A=p (1-r)^t
A future value?
P present value 180
R rate of decreases 0.6
T time 2 years
A=180×(1−0.6)^(2)
A=180×(0.4)^(2)
A=28.8
Answer:
it should equal one but i don't know whats in the drop down box