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kherson [118]
2 years ago
15

How do I find x and what is x

Mathematics
2 answers:
o-na [289]2 years ago
8 0

Answer:

x = 20 degrees

Explanation:

With a 20 degree angle on the direct opposite side, it shows that x is also 20 degrees; and the other two angles would be 160 degrees.

Hope this helps :)

Andreyy892 years ago
6 0

Step-by-step explanation:

x= 20 degrees

The angles opposite each other when two lines cross are called vertically opposite angles and are equal

optionA

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For f(x) = x2 and g(x) = (x − 5)2, in which direction and by how many units should f(x) be shifted to obtain g(x)? (5 points) Up
IgorC [24]

Answer:

5 units to the right.

Step-by-step explanation:

The x in f(x) is replaced by x - 5 to give g(x).

The - 5 will shift f(x) 5 units to the right.

3 0
2 years ago
Plz help..............
IrinaVladis [17]
The correct answer is -15 because the absolute value is 15 but there is a negative outside the absolute value lines making it negative :)
7 0
3 years ago
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An area is approximated to be 14 in 2 using a left-endpoint rectangle approximation method. A right- endpoint approximation of t
USPshnik [31]
The trapezoidal approximation will be the average of the left- and right-endpoint approximations.

Let's consider a simple example of estimating the value of a general definite integral,

\displaystyle\int_a^bf(x)\,\mathrm dx

Split up the interval [a,b] into n equal subintervals,

[x_0,x_1]\cup[x_1,x_2]\cup\cdots\cup[x_{n-2},x_{n-1}]\cup[x_{n-1},x_n]

where a=x_0 and b=x_n. Each subinterval has measure (width) \dfrac{a-b}n.

Now denote the left- and right-endpoint approximations by L and R, respectively. The left-endpoint approximation consists of rectangles whose heights are determined by the left-endpoints of each subinterval. These are \{x_0,x_1,\cdots,x_{n-1}\}. Meanwhile, the right-endpoint approximation involves rectangles with heights determined by the right endpoints, \{x_1,x_2,\cdots,x_n\}.

So, you have

L=\dfrac{b-a}n\left(f(x_0)+f(x_1)+\cdots+f(x_{n-2})+f(x_{n-1})\right)
R=\dfrac{b-a}n\left(f(x_1)+f(x_2)+\cdots+f(x_{n-1})+f(x_n)\right)

Now let T denote the trapezoidal approximation. The area of each trapezoidal subdivision is given by the product of each subinterval's width and the average of the heights given by the endpoints of each subinterval. That is,

T=\dfrac{b-a}n\left(\dfrac{f(x_0)+f(x_1)}2+\dfrac{f(x_1)+f(x_2)}2+\cdots+\dfrac{f(x_{n-2})+f(x_{n-1})}2+\dfrac{f(x_{n-1})+f(x_n)}2\right)

Factoring out \dfrac12 and regrouping the terms, you have

T=\dfrac{b-a}{2n}\left((f(x_0)+f(x_1)+\cdots+f(x_{n-2})+f(x_{n-1}))+(f(x_1)+f(x_2)+\cdots+f(x_{n-1})+f(x_n))\right)

which is equivalent to

T=\dfrac12\left(L+R)

and is the average of L and R.

So the trapezoidal approximation for your problem should be \dfrac{14+21}2=\dfrac{35}2=17.5\text{ in}^2
4 0
2 years ago
A circular garden is enlarged so that the new diameter is twice the old diameter. What is the ratio of the original area to the
Amanda [17]

Answer:

  • Explained briefly below.

Step-by-step explanation:

<u>For old circular garden:</u>

take the radius as r.

then use the formula to find area of circle: πr² ......this is old garden area.

<u>For new enlarged garden:</u>

the radius is twice the old radius so, radius = 2 * r = 2r ......enlarged radius

now find area for this new garden:  π(2r)² → 4πr²

In common fractions: (old garden)/(new garden)

                                : ( πr² ) / ( 4πr² )

                                 :    1/4

7 0
2 years ago
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Mr. smith has 5 courses he teaches at the community college. his course a has 102 students with an average tardiness of 3 studen
Furkat [3]

The percentage of tardiness among the 102 pupils is 2.94.

<h2>Calculation of the percentage</h2>

According to the query,

Course A: Total number of students = 102

                   Number of tardy students = 3

Percent of students tardy in course A = (number of tardy students/total  

                                                                   number of students) * 100

  =(3/102)*100

  = 2.941

  ≈2.94

In case of course B: Total number of students = 85 & tardy student = 5

So, the percent of tardy student = (5/85)*100 = 5.88 %

Therefore, it is concluded that the percentage of student tardiness in course A is 2.94.

Learn more about the percentage here:

brainly.com/question/92258

#SPJ4

5 0
2 years ago
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