Answer:
These metals exist in only one ion; therefore, they cannot give away more than one ion. Thus, even though they are transition metals, aluminum, zinc and silver are only (I) and never require Roman numerals written after their names.
Explanation:
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Answer:
Explanation:
For the reaction: 2X + 3Y = 3Z, the combination of 2.00 moles of X with 2.00
moles of Y produces 1.75 moles of Z
2 mol 2 mol 1.75 mol
2X + 3Y = 3Z
need 2 mol 3 mol to give 3 mol
3 mol Z/3 mol Y= 1 to 1
should get 2 mol Z
1.75/2 =87.5 % yield
4- KOH
KOH is a strong base. In water it dissociates as
<span>KOH--> K+ + OH- </span>
<span>A is acetic acid, a weak acid </span>
<span>CH3OH is an alcohol, weakly acidic in water </span>
<span>HCl is a strong acid.</span>
Answer:
A. Solid aluminum oxide and solid iron
Explanation:
The reaction equation is given as:
2Al + Fe₂O₃ → Al₂O₃ + 2Fe
The species on the left hand side are the reactants
Those on the right hand side of the expression are the products.
The products are:
Al₂O₃ and Fe
These are solid aluminum oxide and solid iron
Answer:
See explanation.
Explanation:
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In this case, we consider the questions:
a. Ideal gas at:
i. 273.15 K and 22.414 L.
ii. 500 K and 100 cm³.
b. Van der Waals gas at:
i. 273.15 K and 22.414 L.
ii. 500 K and 100 cm³.
Thus, we define the ideal gas equation and the van der Waals one as shown below:
Whereas b and a for hydrogen sulfide are 0.0434 L/mol and 4.484 L²*atm / mol² respectively, therefore, we proceed as follows:
a.
i. 273.15 K and 22.414 L.
ii. 500 K and 100 cm³ (0.1 L).
b.
i. 273.15 K and 22.414 L: in this case, v = 22.414 L / 1.00 mol = 22.414 L/mol
ii. 500 K and 100 cm³: in this case, v = 0.1 L / 1.00 mol = 0.100 L/mol
Whereas we can see a significant difference when the gas is at 500 K and occupy a volume of 0.100 L.
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