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shtirl [24]
3 years ago
9

The thermometer in the picture reads, "19.9 degrees Celsius".

Chemistry
1 answer:
GalinKa [24]3 years ago
6 0

Answer:

Sorry but i can't help

Explanation:

i need to really finesh s

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H2S (g) + O2(g) -> SO2+ H2O, how many grams of O2 are needed to make 25.0 g of SO2 (Hint: balance the equation first)
vekshin1

Answer:

Hello

The answer is 18,7(b)

Explanation:we don't know the value of o² so at first we should put (x)instead of gr of o²and then write 1molO²/32grO²×2mol SO²/3mol O²×64gr SO²/1molSO²=25 gr SO².and then just find the value of (x).

5 0
3 years ago
Vincent graduated from college with a degree in horticulture and now owns a local plant nursery. He maintains a blog titled, "Ho
Mamont248 [21]

Answer: Option (C) is the correct answer.

Explanation:

Horticulture is the study of science related to the art of growing fruits, vegetables, or plants.

Therefore, when a person graduated from a college with a degree in horticulture then it means he has obtained enough knowledge about how to grow plants, fruits or vegetables in the best way possible.

Thus, Vincent who also graduated in horticulture cannot accurately tell about human psychology.

Hence, we can conclude that the statement this claim may not be accurate because the blog is produced by someone who is not an expert in the field of human psychology.


7 0
4 years ago
Read 2 more answers
a culinary student fills a 40ml container with 37.2 grams of vegetable oil.What is the density of the oil
Lynna [10]

Answer:

<h2>0.93 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

From the question

mass = 37.2 g

volume = 40 mL

We have

density =  \frac{37.2}{40}  \\  = 0.93

We have the final answer as

<h3>0.93 g/mL</h3>

Hope this helps you

4 0
3 years ago
The freezing point of ethanol, CH3CH2OH, is -117.300 °C at 1 atmosphere. Kf(ethanol) = 1.99 °C/m
MAXImum [283]

Answer : The molecular weight of this compound is 891.10 g/mol

Explanation :  Given,

Mass of compound = 12.70 g

Mass of ethanol = 216.5 g

Formula used :  

\Delta T_f=i\times K_f\times m\\\\T_f^o-T_f=i\times T_f\times\frac{\text{Mass of compound}\times 1000}{\text{Molar mass of compound}\times \text{Mass of ethanol}}

where,

\Delta T_f = change in freezing point

T_f^o = temperature of pure ethanol = -117.300^oC

T_f = temperature of solution = -117.431^oC

K_f = freezing point constant of ethanol = 1.99^oC/m

i = van't hoff factor = 1   (for non-electrolyte)

m = molality

Now put all the given values in this formula, we get

(-117.300)-(-117.431)=1\times 1.99^oC/m\times \frac{12.70g\times 1000}{\text{Molar mass of compound}\times 216.5g}

\text{Molar mass of compound}=891.10g/mol

Therefore, the molecular weight of this compound is 891.10 g/mol

7 0
3 years ago
25 points!!! please Which types of elements areconsidered neutraland Where are these types of elements found on the periodic tab
posledela

Elements which composed of an equal amount of three components protons, neutrons and electrons are considered neutral elements. example of neutral elements are hydrogen, helium, lithium and beryllium...

7 0
3 years ago
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