Answer:
B:with increase in number of valence electrons
Explanation:
As we move from left to right across the periodic table the number of valance electrons in an atom increase. The atomic size tend to decrease in same period of periodic table because the electrons are added with in the same shell. When the electron are added, at the same time protons are also added in the nucleus. The positive charge is going to increase and this charge is greater in effect than the charge of electrons. This effect lead to the greater nuclear attraction. The electrons are pull towards the nucleus and valance shell get closer to the nucleus. As a result of this greater nuclear attraction atomic radius decreases and ionization energy increases because it is very difficult to remove the electron from atom and more energy is required.
Answer:
The answer to your question is 2 moles of Carbon
Explanation:
Carbon-12 means it has a molecular mass of 12g / mol. Mol is defined as the number of grams of an atom in one mol.
To solve this problem, we use proportions
12 g of Carbon ---------------- 1 mol of Carbon
24 g of Carbon -------------- x
x = ( 24 g x 1 mol ) / 12 g
x = 24 / 12
x = 2 mol of Carbon
Answer:
45.13 psi
Explanation:
Assuming the volume does not change
P1/T1 = P2/T2 T must be in Kelvin
40/(273.15) = P2/(273.15 + 35) P2 = 45.13 psi
The molarity of the hydrochloric acid, HCl solution given the data is 0.079 M
<h3>Balanced equation </h3>
HCl + NaOH —> NaCl + H₂O
From the balanced equation above,
- The mole ratio of the acid, HCl (nA) = 1
- The mole ratio of the base, NaOH (nB) = 1
<h3>How to determine the molarity of HCl </h3>
- Molarity of base, NaOH (Mb) = 0.137 M
- Volume of base, NaOH (Vb) = 16.1 mL
- Volume of acid, HCl (Va) = 27.9 mL
- Molarity of acid, HCl (Ma) =?
MaVa / MbVb = nA / nB
(Ma × 27.9) / (0.137 × 16.1) = 1
(Ma × 27.9) / 2.2057 = 1
Cross multiply
Ma × 27.9 = 2.2057
Divide both side by 27.9
Ma = 2.2057 / 27.9
Ma = 0.079 M
Thus, the molarity of the HCl solution is 0.079 M
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Answer:
Therefore, the oxidation state of sulphur atoms in Na2S2O3 is −2 and +6.
