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2 years ago

I can't figure it out. 2x+2y=2-4x+4y=12

Mathematics

1 answer:

koban [17]2 years ago

6 0

Answer:

how to solve 2x+2y=2 , -4x+4y=12

this is solving equations using substitution .... i have ALOT more but i juss dnt get this stuff

2x + 2y = 2 -4x + 4y = 12

x + y = 1

x = 1 - y

-4x + 4y = 12

-4(1 - y) + 4y = 12

(-4 + 4y) + 4y = 12

-4 + 8y = 12

8y = 16

y = 2

2x + 2y = 2

2x + 2(2) = 2

2x + 4 = 2

2x = -2

x = -1

Check.

-4x + 4y = 12

-4(-1) + 4(2) = 12

4 + 8 = 12

Answer: x = -1 and y = 2

Step-by-step explanation:

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A 98% confidence interval for the mean assembly time is [21.34, 26.49] .

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Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

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Here for constructing a 98% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation.

So, a 98% confidence interval for the population mean, $\mu$ is;

P(-2.426 < $t_3_9$ < 2.426) = 0.98 {As the critical value of z at 1% level

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P(-2.426 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 2.426) = 0.98

P( $-2.426 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $2.426 \times {\frac{s}{\sqrt{n} } }$ ) = 0.98

P( $\bar X-2.426 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+2.426 \times {\frac{s}{\sqrt{n} } }$ ) = 0.98

98% confidence interval for $\mu$ = [ $\bar X-2.426 \times {\frac{s}{\sqrt{n} } }$ , $\bar X+2.426 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $23.92-2.426 \times {\frac{6.72}{\sqrt{40} } }$ , $23.92+2.426 \times {\frac{6.72}{\sqrt{40} } }$ ]

= [21.34, 26.49]

Therefore, a 98% confidence interval for the mean assembly time is [21.34, 26.49] .

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2 years ago

I can't figure it out. 2x+2y=2-4x+4y=12​

I can't figure it out. 2x+2y=2-4x+4y=12