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2 years ago

Should the United States return to a gold standard? Why?

Mathematics

1 answer:

cupoosta [38]2 years ago

3 0

Answer:

Step-by-step explanation:

If the U.S goes in a gold standard it can put the whole state in a crises

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On a hot day, Ava poured 1/4 of a bucket of water into a plastic wading pool.a few minutes later she added another 1/3 of a buck

faltersainse [42]

Answer:

7/12

Step-by-step explanation:

4 x 3 = 12 (LCD)

3/12 + 4/12 = 7/12

No simplifying done,

7/12 is the answer.

Hope this helped :)

5 0

2 years ago

How much money left after spending $8, $7 and $13, then received $10 and spent $15. now $12 is left. how much money did one have

Inessa [10]

$8 + $7 + $13 + 15 = $43
$x - $43 = $12
x = $55

i am a mathematics teacher. if anything to ask please pm me

4 0

3 years ago

What is √18x^6 written in simplest for? assume all variables are positive.

Nadya [2.5K]

Your answer should be C. 3x^3√2

3 0

3 years ago

1 & 2

sveta [45]

The value of x is 13 for the first attachment.

5 0

3 years ago

Explain how to get that answer!!

ra1l [238]

We need to simplify $\frac{ \sqrt{14x^3} }{ \sqrt{18x} }$

First lets factor $\sqrt{14x^3}$

$\sqrt{14x^3}$ = $\sqrt{14} \sqrt{x^3}$
$\sqrt{14} = \sqrt{2} \sqrt{7}$ by applying the radical rule $\sqrt[n]{ab} = \sqrt[n]{a} \sqrt[n]{b}$
$\sqrt{x^3} = x^{3/2}$ By applying the radical rule $\sqrt[n]{x^m} = x^{m/n}$

So
$\sqrt{14x^3}$ = $\sqrt{14} \sqrt{x^3}$ = $\sqrt{2} \sqrt{7}x^{3/2}$

Now let's factor $\sqrt{18x}$
By applying the radical rule $\sqrt[n]{ab} = \sqrt[n]{a} \sqrt[n]{b}$ ,
$\sqrt{18x} = \sqrt{18} \sqrt{x}$
$\sqrt{18} = \sqrt{2} * 3$

So $\sqrt{18x}$ = $\sqrt{2}*3 \sqrt{x}$

So $\frac{ \sqrt{14x^3} }{ \sqrt{18x} }$ = $\frac{ \sqrt{2} \sqrt{7} x^{3/2} }{ \sqrt{2}*3 \sqrt{x} }$

We know that $\sqrt[n]{x} = x^{1/n}$ so $\sqrt{x} = x^{1/2}$

We now have $\frac{ \sqrt{2} \sqrt{7} x^{3/2} }{ \sqrt{2}*3 \sqrt{x}} = \frac{ \sqrt{2} \sqrt{7} x^{3/2} }{ \sqrt{2}*3x^{1/2}}$

We know that $\frac{x^a}{x^b} = x^{a-b}$
So $\frac{x^{3/2}}{x^{1/2}} = x^{3/2 - 1/2} = x$

We now got $\frac{ \sqrt{2} \sqrt{7} x^{3/2} }{ \sqrt{2}*3x^{1/2}} = \frac{ \sqrt{2} \sqrt{7} x }{ \sqrt{2}*3}
$

We can notice that the numerator and the denominator both got √2 in a multiplication, so we can simplify them, and we get:
$\frac{ \sqrt{2} \sqrt{7} x }{ \sqrt{2}*3} = \frac{ \sqrt{7}x }{3}$

All in All, we get $\frac{ \sqrt{14x^3} }{ \sqrt{18x} }$ = $\frac{ \sqrt{7}x }{3}$

Hope this helps! :D

6 0

3 years ago