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3 years ago

Which expression or equivalent to the one below Check all that apply Log ^9 1 • log^9 81

1 answer:

5 0

$\log_91\cdot\log_981=\log_99^0\cdot\log_99^2=0\log_99\cdot2\log_99=0\cdot1\cdot2\cdot1=0\\\\Used:\\\\\log_ab^n=n\log_ab\\\\\log_aa=1\\---------------------\\\\\log_a1=0\ because\ a^0=1,\ therefore\\\\\log_91\cdot\log_981=0\cdot\log_981=0$

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Sine theta equals square root of 3 over 2 find theta.

Alexxx [7]

Sin(theeta) = square root(3)/2
theeta = sin inverse [square root (3)/2]
theeta = 60 degrees
as seen from trignometric table

7 0

3 years ago

Y= - x+2 Y=3x-4 Estimate the solution to the system of equations

IrinaVladis [17]

Answer:

$x=\frac{3}{2}\\ y=\frac{1}{2}$

Step-by-step explanation:

$y=-x+2\\y=3x-4$

Let's solve one of them for x.

$y=3x-4$

Add 4

$y+4=3x$

Divide by 3.

$x=\frac{y+4}{3}$

Now, plug the value of y in the formula, or you can plug the value of x in the other equation. I'll take this one.

$x=\frac{y+4}{3}$

$x=\frac{(-x+2)+4}{3}$

$x=\frac{-x+2+4}{3}$

$x=\frac{-x+6}{3}$

Multiply by 3 to get rid of the denominator.

$3x=-x+6$

add x

$3x+x=6$

Combine like terms;

$4x=6$

Divide by 4.

$x=\frac{6}{4}$

Simplify.

$x=\frac{3}{2}$

Now that you found the value of x, replace it in any of the equations to find y.

$y=-x+2\\y=-(\frac{3}{2})+2\\ y=-\frac{3}{2}+2$

$y=\frac{-3+2*2}{2} \\y=\frac{-3+4}{2} \\y=\frac{1}{2}$

Proof:

$y=3x-4\\\frac{1}{2}=3(\frac{3}{2})-4\\\frac{1}{2}=(\frac{9}{2})-4$

$\frac{1}{2}=\frac{9-4*2}{2}$

$\frac{1}{2}=\frac{9-8}{2}$

$\frac{1}{2}=\frac{1}{2}$

8 0

3 years ago

If x=-6, which inequality is true ??

Gelneren [198K]

Answer:

The inequality that is true is -5 - 3x > 10.

Step-by-step explanation:

if x = -6

we can subtitution x to every inequality, so :

-5 - 3x > 10

-5 - 3(-6) > 10

-5 - (-18) > 10

-5 + 18 > 10

13 > 10 [true]

-3 - 5x < -14

-3 - 5(-6) < -14

-3 - (-30) < -14

-3 + 30 < -14

27 < -14 [false]

2 - x < -3

2 - (-6) < -3

2 + 6 < -3

8 < -3 [false]

So if x=-6, inequality true is -5 - 3x > 10.

If this was helpful, please mark brainliest. Have a beautiful day.

4 0

3 years ago

If u-ai + bj and v-ci + dj are vectors, then which of the following statements is not true?

alukav5142 [94]

Answer:

Option C

Step-by-step explanation:

Given that u-ai + bj and v-ci + dj are vectors

We have dot product

$u.v = (ai+bj).(ci+dj)$ hence inner product of u and v. So option a is true

The dot product of u and v is a scalar is true because dot product is always a scalar

The dot product of u and v is a vector. is false because dot product is only a scalar and has no direction and hence cannot be a vector

The dot product of u and v is given by the expression ac+bd

True because we multiply corresponding i components and j components and add.

So only C is not true.

7 0

3 years ago

I NEED HELP PLEASE, THANKS! :)

NISA [10]

Answer: $\bold{b)\quad \dfrac{2\pi}{3},\dfrac{4\pi}{3},0}$

Step-by-step explanation:

Note the following identities: tan² x = sec²x - 1

$\sec x=\dfrac{1}{\cos}$

tan² x + sec x = 1

(sec² x -1) + sec x = 1

sec² x + sec x - 2 = 0

(sec x + 2)(sec x - 1) = 0

sec x + 2 = 0 sec x - 1 = 0

sec x = -2 sec x = 1

$\dfrac{1}{\cos x}=-2\qquad \dfrac{1}{\cos x}=1\\\\\cos x=-\dfrac{1}{2}\qquad \cos x=1\\\\x=\dfrac{2\pi}{3}, \dfrac{4\pi}{3}\qquad x=0$

8 0

3 years ago

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