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ycow [4]
2 years ago
14

Which expression or equivalent to the one below Check all that apply Log ^9 1 • log^9 81

Mathematics
1 answer:
kodGreya [7K]2 years ago
5 0

\log_91\cdot\log_981=\log_99^0\cdot\log_99^2=0\log_99\cdot2\log_99=0\cdot1\cdot2\cdot1=0\\\\Used:\\\\\log_ab^n=n\log_ab\\\\\log_aa=1\\---------------------\\\\\log_a1=0\ because\ a^0=1,\ therefore\\\\\log_91\cdot\log_981=0\cdot\log_981=0

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What’s the answer and the work ?
Phoenix [80]

Answer:

2√14

Step-by-step explanation:

√56

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5 0
3 years ago
A top-loading washing machine has a cylindrical basket that rotates about a vertical axis. The basket of one such machine starts
damaskus [11]

Answer:

n_{tot}=44rev

Step-by-step explanation:

In order to solve this problem we can make use of the following formula:

\theta=(\frac{\omega_{f}+\omega_{0}}{2})t

where θ is the total angle the basket has turned, ω is the angular velocity and t is the time.

Generally theta is written in radians and omega is written in radians per second. Now, since the revolutions are directly related to the radians and they want us to write our answer in revolutions, we can directly use the provided speeds in the formula, so we can rewrite it as:

n=(\frac{f_{f}+f_{0}}{2})t

where n represents the number of revolutions and f is the frequency at which the basket is turning.

The movement of the cylindrial basket can be split in two stages, when it accelerates and when it decelerates. So let's analye the first stage:

n=(\frac{4rev/s+0}{2})(9s)=18rev

and now let's analyze the second stage, where it decelerates, so we get:

n=(\frac{0rev/s+4rev/s}{2})(13s)=26rev

So now that we know how many revolutions the cylindrical basket will take as it accelerates and as it decelerates we can add them to get:

n=18rev+26rev=44rev

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Answer:

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Step-by-step explanation:

The computation of the area of the circle is shown below:

As we know that

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= 4π

hence, the area of the circle is 4π

8 0
2 years ago
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