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dexar [7]
2 years ago
10

All i need help with is this please

Mathematics
1 answer:
Diano4ka-milaya [45]2 years ago
8 0
I believe the correct answer is 35
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A regular triangular pyramid has a base and lateral faces that are congruent equilateral triangles. It has a lateral surface are
TEA [102]
We know that

[lateral surface area of a regular triangular pyramid]=3*[area of one <span>equilateral triangle]
so
[area of one </span>equilateral triangle]=lateral surface/3-----> 81/3-----> 27 ft²

[<span>surface area of the regular triangular pyramid]=lateral area+area of the base

area of the base is equals to the area of the lateral sides because are </span>equilateral triangles

therefore
area of the base=27 ft²

[surface area of the regular triangular pyramid]=81+27----> 108 ft²

the answer is
<span>the surface area of the regular triangular pyramid is 108 ft</span>²
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2 years ago
Which is the leastt common multiple for 3 and 9
postnew [5]

Answer:

9

Step-by-step explanation:

4 0
3 years ago
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Write the product using exponents.<br><br> 6.4.6.4.6.4.6.4.b.b.b
maks197457 [2]

Step-by-step explanation:

I count four 6s, four 4s and three b.

so, we have

6⁴×4⁴×b³ or (using the same symbols as above)

6⁴.4⁴.b³

4 0
2 years ago
FOR ALL YOU STAR WARS FANS OUT THERE MY TEACHER GAVE US A STAR WARS MATH QUESTION. CHECK MY ANSWER MYBE? He asked how fast a bla
kvv77 [185]
(Links in comments below)

I'm using the clip from link [1] as a reference, i.e. the shot of the Tantive IV escaping the Devastator towards the camera, which lasts approximately 5 seconds (2:27 - 2:32). I recorded the particular shot, then carried out a cursory frame-by-frame analysis. The shot itself consists of 371 frames.

At around frame 15 - about 0.233s into the clip - one can barely make out a green projectile being launched from one of the Devastator's batteries. It takes the projectile between 19 and 20 frames (I'll round up to 20) - now at frame 35, about 0.333s later - for it to reach the left edge of the camera's field of view.

Let's suppose the Tantive IV was situated in roughly the same physical position in frame 1 as the projectile was in frame 35.

Now, the Tantive IV exits the screen at around frame 182 - about 3.017s into the clip. According to link [2], the standard CR90 "Corellian" Corvette can reach speeds of up to 950km/h. The Rebels are fleeing the Empire, so it's reasonable to assume that they are moving as fast as they can. Let's also assume they're traveling at a constant rate, and that the tractor beam aboard the Devastator hasn't been activated yet.

Note: Link [2] refers to this maximum speed as "atmosphere speed". I can't find any references as to what this means, so I assume it means something along the lines of "same conditions as Earth's atmosphere". The two ships are flying above Tatooine, which is inhabited in part by humans, so it's probably a safe bet that the atmospheres of Tatooine and Earth aren't that dissimilar.

So if it takes the Tantive IV about 3.017s to move (approximately) the same distance as the Devastator's projectile, and if we assume the Tantive IV is moving at maximum speed, then it must have traveled a distance d of (approximately)

d=\dfrac{950\text{ km}}{1\text{ h}}\times(3.017\text{ s})\implies d\approx0.796\text{ km}

However, it's quite clear from the previous shot that the assumption above is not all that accurate. So let's consider "your" assumption, that the distance between the Tantive IV and the Devastator is about 10 times its own length, i.e. d\approx2.296\text{ km}. Now, if the projectile takes about 0.333s to travel the same distance, then it must have moving at a speed r of (approximately)

2.296\text{ km}=r\times(0.333\text{ s})\implies r\approx24,821.6\dfrac{\text{km}}{\text{h}}
3 0
2 years ago
Stephen counted 17 heartbeats in 15 seconds. How many times does his heart beat in 1 minute?
blagie [28]

Stephen's heart beats 68 times in one minute

Step-by-step explanation:

60 sec (one min) divided by 15 sec ( the unit of time we use to track the 17 heartbeats) = 4

4 times 17 =68

6 0
2 years ago
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